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Georgia [21]
3 years ago
10

A ball starts from rest and accelerates at 0.465 m/s2 while moving down an inclined plane 8.20 m long. When it reaches the botto

m, the ball rolls up another plane, where, after moving 16.7 m, it comes to rest. What is the speed of the ball at the bottom of the first plane?
Physics
1 answer:
Zepler [3.9K]3 years ago
6 0

Answer:

2.76m/s

Explanation:

The position x for a given time t and constant acceleration a is:

(1) x=\frac{1}{2}at^2

The velocity v:

(2) v=at

Solving equation 2 for time t:

(3) t=\frac{v}{a}

Combining equations 1 and 3:

(4) x=\frac{v^2}{2a}

Solving equation 4 for velocity v:

(5) v=\sqrt{2ax}

For a = 0.465m/s² and x = 8.2m:

v = 2.76m/s

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A thin, flat washer is a disk with an outer diameter of 14 cm and a hole in the center with a diameter of 7 cm. The washer has a
Kryger [21]

Answer:

2583.9 N/C

Explanation:

Parameters given:

Outer diameter = 14 cm

Outer radius, R = 7cm = 0.07m

Inner diameter = 7 cm

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The electric field due to a washer (hollow disk) is given as:

E = k * σ * 2π [ 1 - z/(√(z² + R²)]

Where σ = charge per unit area

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4 years ago
A total of 25.6 kJ of heat energy is added to a 5.46 L sample of helium at 0.991 atm. The gas is allowed to expand against a fix
bagirrra123 [75]

Answer:

(a) W = 1329.5 J = 1.33 KJ

(b) ΔU = 24.27 KJ

Explanation:

(a)

Work done by the gas can be found by the following formula:

W = P\Delta V

where,

W = Work = ?

P = constant pressure = (0.991 atm)(\frac{101325\ Pa}{1\ atm}) = 100413 Pa

ΔV = Change in Volume = 18.7 L - 5.46 L = (13.24 L)(\frac{0.001\ m^3}{1\ L}) = 0.01324 m³

Therefore,

W = (100413 Pa)(0.01324 m³)

<u>W = 1329.5 J = 1.33 KJ</u>

<u></u>

(b)

Using the first law of thermodynamics:

ΔU = ΔQ - W (negative W for the work done by the system)

where,

ΔU = change in internal energy of the gas = ?

ΔQ = heat added to the system = 25.6 KJ

Therefore,

ΔU = 25.6 KJ - 1.33 KJ

<u>ΔU = 24.27 KJ</u>

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