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kati45 [8]
4 years ago
13

What voltage indicates the voltmeter connected to the ends of a conductor, if the ammeter connected in series with this conducto

r indicates a current of 400 mA. The resistance of the conductor is equal to 5kΩ.
Physics
1 answer:
ycow [4]4 years ago
3 0

Explanation:

V= Current × Resistance

V= 400mA × 5kohms

V= 2000V

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I need some serious help, i do not understand this question!!
Shkiper50 [21]

The position where the package strikes the ground is 136.3m.

<h3>Time of motion of the package</h3>

Use the following kinematic equation;

h = vt + ¹/₂gt²

179 = 47t  +  ¹/₂(9.8)t²

179 = 47t + 4.9t²

4.9t² + 47t - 179 = 0

solve the quadratic equation using formula method;

a = 4.9, b = 47, c = -179

t = 2.9 seconds

<h3>Horizontal distance traveled by the package</h3>

X = vt

X = 47m/s x 2.9 s

X = 136.3 m

Thus, the position where the package strikes the ground is 136.3m.

Learn more about time of motion here: brainly.com/question/2364404

#SPJ1

4 0
2 years ago
A woman (m = 45kg) is kneeling on the shoulders of a man (m = 70kg) in pair figure-skating while both are traveling at 1.5 m/s.
Temka [501]

Both the man and the woman will be experiencing the same impulse, due to Newton's third law of motion.

Explanation:

This problem considers law of conservation of momentum as well as Newton's third law of motion. As per the third law of motion, every action has an equal and opposite reaction. And the law of conservation of momentum states that the momentum is conserved after collision.

Since, here the woman is kneeling on the man, it is similar to inelastic collision where the man and woman are moving with same velocity. And as the man accelerates the woman, the woman will exhibit a forward force. While at the same time, the man will be experiencing a backward force of same magnitude as of the woman. This is in consistence with the third law of motion.

So both the man and woman will experience force of same magnitude but opposite in direction. As impulse is directly proportional to the force acting on any object in a given duration, so both the man and the woman will be experiencing the same impulse.

3 0
4 years ago
An astronaut stands on the surface of an asteroid. The astronaut then jumps such that the astronaut is no longer in contact with
Anna71 [15]

(D) The gravitational force between the astronaut and the asteroid.

Reason :

All the other forces given in the options, except (D), doesn't account for the motion of the astronaut. They are the forces that act between nucleons or atoms and neither of them accounts for an objects motion.

6 0
3 years ago
The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static fricti
Colt1911 [192]

This question is incomplete, the complete question;

The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static friction at A is μ = 0.4.

Determine the magnitude of force at point A and determine if the ladder will slip. given the following; L = 10 FT, W = 76 lb

Answer:

- the magnitude of force at point A is 79.1033 lb

- since FA < FA_max; Ladder WILL NOT slip

Explanation:

Given that;

∑'MA = 0

⇒ NB [Lsin∅] - W[L/2.cos∅] = 0

NB = W / 2tan∅ -------let this be equation 1

∑Fx = 0

⇒ FA - NB = 0

FA = NB

therefore from equation 1

FA = NB = W / 2tan∅

we substitute in our values

FA = NB = 76 / 2tan(60°) = 21.9393 lb

Now ∑Fy = 0

NA - W = 0

NA = W = 76 lb

Net force at A will be

FA' = √( NA² + FA²)

= √( (W)² + (W / 2tan∅)²)

we substitute in our values

FA' = √( (76)² + (21.9393)²)

= √( 5776 + 481.3328)

= √ 6257.3328

FA' = 79.1033 lb

Therefore the magnitude of force at point A is 79.1033 lb

Now maximum possible frictional force at A

FA_max = μ × NA

so, FA_max = 0.4 × 76

FA_max = 30.4 lb

So by comparing, we can easily see that the actual friction force required for keeping the the ladder stationary i.e (FA) is less than the maximum possible friction available at point A.

Therefore since FA < FA_max; Ladder WILL NOT slip

5 0
3 years ago
Please help!!<br><br> please answer if you know any of them!
PSYCHO15rus [73]

Answer:

5. 343j

Explanation:

6 0
3 years ago
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