1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kati45 [8]
3 years ago
13

Is sodium hydroxide an elementary substance or a compound?

Chemistry
1 answer:
mixer [17]3 years ago
7 0

Answer:Sodium hydroxide, also known as lye and caustic soda, is an inorganic compound

Explanation:

It is a white solid ionic compound consisting of sodium cations Na+ and hydroxide anions OH−

You might be interested in
Rules for naming compounds are beneficial to the scientific community.
blondinia [14]
Agree with the statement buddy
8 0
3 years ago
Read 2 more answers
In what orbital would to valence electrons of strontium be found? a.) 5s b.) 4s c.) none d.) 5p​
KonstantinChe [14]

Answer:

The correct answer is 5s

Explanation:

Strontium atomic number = 38

Electronic configuration is $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 3d^{10} 4s^{2} 4p^{6} 5s^{2}

As $5s$ orbital is valence orbital in strontium, the outer electrons exists in that orbital only.

4 0
2 years ago
How many atoms are in 25.00 g of B?
klio [65]

Answer:

There are 1.393 x 10²⁴ atoms in 25.00 g of B.

Explanation:

Hey there!

We are given a value, in grams, that we need to convert to a number of atoms.

We can convert grams to atoms by using Avogadro's Number (N_A). This number is equivalent to 6.022 \times 10^{23}.

This number can be used to convert any values to:

  • atoms
  • molecules
  • formula units
  • moles

In order to do this problem, we will need to use dimensional analysis (DA). This process allows us to convert from grams to atoms.

We need to set up our ratios in order to work this out. We can use a periodic table to help us through this next part of the problem.

<u>1. Locating the number of moles of B in the sample</u>

We first need to find the amount of moles of boron (B) there are in the sample.

Checking a periodic table, the atomic mass in atomic mass units (amu) is 10.81 amu.

  • Atomic mass units can easily be converted to grams and these units can be used interchangeably.

Therefore, for each atom of boron, it weighs 10.81 grams to us. This is equivalent to the mass of one mole of boron.

To find the number of moles, we have two possible ratios we can use:

  • \displaystyle \frac{1 \ mole \ B}{10.81 \ grams \ B}
  • \displaystyle \frac{10.81 \ grams \ B}{1 \ mole \ B}

These ratios mean the same thing, but we need to convert our final unit to moles.

We are given a sample in grams, and when dividing our units, we need to keep moles.

Since the first portion of our expression is in grams, we need to have grams in the bottom of our expression.

  • \displaystyle 25.00 \ \text{grams B} \ \times \frac{1 \text{mole B}}{10.81 \ \text{grams B}}

We can now simplify the expression. Our <u>grams B</u> unit will cancel out, so we are therefore left with <u>moles B</u> remaining.

<u>2. Locating the number of atoms in the sample</u>

Now with our equation, we can convert our number of moles that would be solved if we stopped with the above. However, we need to convert to atoms.

We use Avogadro's number and create a ratio with that of moles.

  • \displaystyle \frac{6.022 \times 10^{23}\text{atoms}}{1 \text{mole B}}
  • \displaystyle \frac{1 \text{mole B}}{6.022 \times 10^{23} \text{atoms}}

We need to cancel out our moles and end with atoms, so we must have moles in the denominator. Therefore, we use the first ratio.

Using our previous expression, we multiply by this new ratio and solve the expression.

  • \displaystyle 25.00 \ \text{grams B} \ \times \frac{1 \text{mole B}}{10.81 \ \text{grams B}} \ \times \frac{6.022 \times 10^{23}\text{atoms}}{1 \text{mole B}}

This expression can now be operated. You will need a calculator to perform this calculation.

<u>Our numerator is:</u>

  • [(25.00 \times 1 \times (6.022 \times 10^{23})]

Plugging this into a calculator, we get:

  • 1.5055 \times 10^{25}

<u>Our denominator is:</u>

  • (1 \times 10.81 \times 1)

This simplifies to:

  • 10.81

<u>Dividing our numerator and denominator:</u>

  • <u />\displaystyle \frac{1.5055 \times 10^{25}}{10.81}<u />

Plugging this into a calculator, we get:

  • 1.392691952 \times 10^{24}

<u>3. Simplifying with significant figures</u>

Now, we need to take into account that we have significant figures. We are given this original value:

  • 25.00

This value has four significant figures, which means we need to round our value we received above to four significant figures.

  • \approx 1.393

Our units are added as well as our scientific notation:

  • 1.393 \times 10^{24} \ \text{atoms of B}

Therefore, our final answer is choice A.

8 0
2 years ago
When aqueous solutions of NH4OH(aq) and CuCl2(aq) are mixed, the products are NH4Cl(aq) and Cu(OH)2(s). What is the net ionic eq
Ilia_Sergeevich [38]

Answer:

2OH^-(aq) + Cu^2+(aq) -----> Cu(OH)2(s)

Explanation:

The net ionic equation usually shows the main ionic reaction that goes in the system. The other ions that do not participate in this net ionic equation are called spectator ions. Spectator ions do not participate in the main reaction occurring in the system.

The net ionic equation quite often result in the formation of a solid precipitate in the system such as Cu(OH)2.

The net ionic equation for this reaction is;

2OH^-(aq) + Cu^2+(aq) -----> Cu(OH)2(s)

5 0
3 years ago
Granite is an intrusive igneous rock with large crystals because it cools slowly. Where was this rock most likely formed?
Irina-Kira [14]

deep inside a volcano because it comes lava

7 0
3 years ago
Other questions:
  • What is the numerical value of Avogadro's number?
    8·1 answer
  • Which type of bond is found between na+ and cl- ions in nacl?
    13·1 answer
  • Emission of which one of the following leaves both atomic number and mass number unchanged?
    6·1 answer
  • Calculate the density of gold (in units of g/mL) if a 5.00 cm cube has a mass of 2.41kg
    6·2 answers
  • At 60 °C the value of Kw is 9.5 x 10-14.
    9·1 answer
  • A sample of i-131 decays from 12 microcuries to 3.0 microcuries in 16 days. what is the half-life of i-131?
    11·1 answer
  • Calculate the density of an object with a mass of 25g and a volume of 10ml
    7·1 answer
  • Can someone help with this please? greatly appreciated!
    11·1 answer
  • If 74.5 m of oxygen are collected at a pressure of 98.0 kPa, what volume will the gas occupy if the
    11·1 answer
  • A cypress tree is the sprout stage. what would you expect to notice when observing this plant?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!