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andreev551 [17]
3 years ago
5

Starting from rest, a truck travels in a straight line for 8.0 s with a uniform acceleration of +1.6 m/s2. The driver then appli

es the brakes for 3.0 s, causing a uniform acceleration of −3.0 m/s2 over that time.(a) What is the truck's speed at the end of the braking period?
(b) What is the total distance traveled by the truck (from the point where it started at rest to the end of the braking period)?
Physics
1 answer:
lana [24]3 years ago
4 0
Because it should be the total number
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Temperature change time base problem. Suppose V = 24 V, I = 0.1 A, for water: mw = 51 gm, cw = 4.18 J/gm ∘K-1, for resistor: mr
nirvana33 [79]

Answer:

t = 444.125 sec

Explanation:

Given data:

V = 24 volt

I  = 0.1 ampere

mass of water mw = 51 gm

cr = 4.18 J/gm degree K^-1

mass of resistor = 8 gm

cr = 3.7 J/gm degree K^-1

we know that power is given as

Power P = VI

But P =E/t

so equating both side we have

\frac{E}{t} = VI

solving for t

t = \frac{E}{VI}

t = \frac{m_w C_w \Delta T}{VI}

t = \frac{51 \times 4.18 \times (5 -0)}{24\times 0.1}

t = 444.125 sec

5 0
3 years ago
Read 2 more answers
A person suffering from anaemia gets tired after a short walk​
FrozenT [24]

Answer:

yes

Explanation:

you will feel weary after shorter times

5 0
3 years ago
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Snail 3, trying to keep up with Snail 2, managed to get to
Kipish [7]

Answer:

Acceleration is the change in velocity over the change in time = Δv/Δt.  To do these problems, you need to find out how much the speed changed and over what period of time it changed.

Snail 1 changes from 4 cm/min to 7 cm/min in 3 minutes.  Subtract the starting velocity (4 cm/min) from the ending velocity (7 cm/min) then divide by the time (3 min):

Snail 1 = (7 cm/min. - 4 cm/min)/(3 minutes) = ?    (remember to put down the units)

Snail 2 changed from 7 cm/min. down to 1 cm/min. in 3 minutes

Snail 2 = (1 cm/min. - 7 cm/min.)/(3 min.) = ?        (note that the acceleration is negative when you slow down)

I hope this helps you

6 0
3 years ago
A tall cylinder contains 30 cm of water. oil is carefully poured into the cylinder, where it floats on top of the water, until t
Art [367]

The total gauge pressure at the bottom of the cylinder would simply be the sum of the pressure exerted by water and pressure exerted by the oil.

The formula for calculating pressure in a column is:

P = ρ g h

Where,

P = gauge pressure

ρ = density of the liquid

g = gravitational acceleration

h = height of liquid

Adding the two pressures will give the total:

P total = (ρ g h)_water + (ρ g h)_oil

P total = (1000 kg / m^3) (9.8 m / s^2) (0.30 m) + (900 kg / m^3) (9.8 m / s^2) (0.4 - 0.30 m)

P total = 2940 Pa + 882 Pa

P total = 3,822 Pa

 

Answer:

 The total gauge pressure at the bottom is 3,822 Pa.

6 0
2 years ago
Read 2 more answers
Calculate the magnitude of the maximum orbital angular momentum Lmax for an electron in a hydrogen atom for states with a princi
erica [24]

Answer:

L_max= 0

Explanation:

The formula for magnitude of maximum orbital angular momentum is given by

L_{max}= \sqrt{l(l+1)\bar{h}}

l= orbital quantum number

l= n-1

n= shell number or principal quantum number

for n=1 , l=0

therefore, L_{max}= \sqrt{0(0+1)\bar{h}}

L_max= 0

3 0
3 years ago
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