Answer:
There will be an increase in the kinetic energy
Explanation:
A falling object converts the gravitational potential energy to the kinetic energy. The potential energy is then converted to kinetic energy followed by the conversation:

where Ep and Ek are potential and kinetic energies respectively.
This potential energy is then converted to kinetic energy. Halfway, the kinetic energy is equal to KE1.
However, the kinetic energy is given by the equation:

As the velocity increases, the kinetic energy increases. Hence KE2 will be greater than KE1
Crest is the part of the wave which does this.
A sound wave is the sample of disturbance resulting from the movement of strength visiting through a medium, including air, water or every other liquid or stable remember as it propagates far from the supply of the sound.
The sound waves are generated by a sound source, such as the vibrating diaphragm of a stereo speaker. The sound source creates vibrations in the surrounding medium. because the supply continues to vibrate the medium, the vibrations propagate far from the supply at the rate of sound, hence forming the sound wave.
A sound wave is not a transverse wave with crests and troughs, however alternatively a longitudinal wave with compressions and rarefactions.
Learn more about wave here:- brainly.com/question/1199084
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<span>If you are looking to get an object up the highest, shoot it straight up. If you want to go for a specific horizontal displacement, use the range equation. R = v2sin(twice the launch angle)/ g. g is the gravitaional constant, 9.8 meters per second. Use degrees for the angle. v is the launch velocity. R is the horizontal displacement. This formula only works if your start altitude and end altitude are the same, i.e. you must shoot over a level field.
it depends on the gravitational force of attraction of earth and air resistance.
if we are neglecting air resistance, the max.horizontal distance is according to this formulae,
V0/2 * sin (2theta)
where V0 is the initial velocity
theta is the angle with x axis and the projection.
There are a number of ways that you could find a horizontally displaced object. You could for example just look.</span>