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4 years ago

A 60 kg bicyclist going 2 m/s increased his work output by 1,800 J. What was his final velocity?

Physics

2 answers:

Alinara [238K]4 years ago

6 0

<em>8 </em>was the correct answer, thanks

Bas_tet [7]4 years ago

3 0

Bicyclist initial kinetic energy is Ek=(1/2)*m*v² where m is his mass and v is his speed and that is equal to:

Ek=(1/2)*60*2²=120 J.

When we add the increased work output, we get the total kinetic energy:

Ek(total)=Ek+W= 120 J + 1800 J= 1920 J

So Ek(total)=1920 J = (1/2)*m*V² where V is the speed after the bicyclist increased his work output. So lets solve for V:

(1/2)*60*V²=1920

30*V²=1920, we divide by 30,

V²=64, and take the square root of both sides,

V=8 m/s.

So the speed of the bicyclist after the increased work output is V=8 m/s.

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(1 points) Find the wavelength of a proton moving at 1.00% of the speed of light. The mass of a proton is 1.67 \times 10^{-27} ~

Iteru [2.4K]

Answer:

The wavelength of the proton will be $1.33\times 10^{-15}\ m$

Explanation:

Given the speed of the proton is $1.00 \%$ of speed of light.

And the mass of the proton is $1.67 \times 10^{-27}\ kg$ ..

We need to find the wavelength of moving proton.

As we know the speed of the light $c=2.998\times 10^8\ m/s$

So, speed of the proton will be

$1.00 \%(c)=\frac{1}{100}\times (c)=0.01\times 2.98\times 10^8\ m/s$

Now, we will use De Broglie's Equation to find out wavelength..

$\lambda =\frac{h}{mv}$

Where

$\lambda$ is the wavelength

$h$ is the Planck's constant $6.626\times 10^{-34}\ m^2\ kg / s$

$m$ is the mass in kg

$v$ is the speed in m/s

$\lambda=\frac{6.626\times 10^{-34}}{1.67 \times 10^{-27}\times 0.01\times 2.98\times 10^8}\\ \\\lambda=\frac{6.626}{1.67\times 0.01\times 2.98}\times 10^{-15}\\ \\\lambda=133.14\times 10^{-15}\ m\\\lambda=1.33\times 10^{-15}\ m$

So, the wavelength of the proton will be $1.33\times 10^{-15}\ m$

7 0

3 years ago

A bicycle traveled 150 meters west from point A to point B. Then it took the same route and came back to point A. It took a tota

Zinaida [17]

Answer:

speed=distance÷time

150÷0. 033

8 0

4 years ago

Read 2 more answers

Now assume that the pitcher in Part D throws a 0.145-kg baseball parallel to the ground with a speed of 32 m/s in the +x directi

pogonyaev

Answer:

V2 = -25.93 m/s

Explanation:

First of all, we know that;

Momentum = mass x change in velocity

Thus;

Momentum = m(v2 - v1)

Also, we know that;

Impulse = force x time

And also that;

Momentum = Impulse

From the question, m = 0.145kg and V1 = 32m/s while impulse = -8.4 N.s

Thus;

0.145(v2 - 32) = -8.4

Now,

0.145v2 - 4.64 = -8.4

0.145v2 = -8.4 + 4.64

0.145v2 = -3.76

v2 = -3.76/0.145

= -25.931 m/s and to two significant figures gives -25.93 m/s

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3 years ago

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3 years ago

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professor190 [17]

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4 years ago

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