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makvit [3.9K]
2 years ago
15

Producer: (plants) (produces its own food) 1. The common name of my organism is: ______________

Physics
2 answers:
Lelu [443]2 years ago
6 0
1. Root
2. Food


This is the answer hope u like it and plz mark me as brainlyist.
Mama L [17]2 years ago
4 0

Answer: 1. Plant

2. Glucose

Explanation:

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Hii please help i’ll give brainliest if you give a correct answer please
Diano4ka-milaya [45]

Answer:

A

Explanation:

6 0
2 years ago
A ball with an initial velocity of zero is dropped from a table onto the ground. After 2 s, the
GenaCL600 [577]
  • Initial velocity=u=0m/s
  • Acceleration=a=10m/s^2
  • Time=t=2s

Final velocity=v

\\ \sf\longmapsto v=u+at

\\ \sf\longmapsto v=0+10(2)

\\ \sf\longmapsto v=20m/s

5 0
2 years ago
Read 2 more answers
A flashlight beam strikes the surface of a pane of glass (n=1.56) at a 71° angle to the normal. What is the angle of refraction?
Aleks04 [339]

Answer:

The angle of refraction is 37°.

Explanation:

let n1 be the refractive index of glass and n2 = 1.0 be the refraction index of air, θ be the angle of incidence , ∅ be the angle of refraction.

then, according to Snell's law:

n1×sin(∅) = n2×sin(θ)

    sin(∅) = n2×sin(θ)/n1

              = (1.0)(sin(71°))/(1.56)

              = 0.606101651

          ∅ = 37°

Therefore, the angle of refraction is 37°.

3 0
3 years ago
What do you mean by impulse ratio?​
mars1129 [50]
<h2>Answer:</h2>

<h3><em><u>The impulse ratio of an insulator can be defined as the ratio of impulse peak voltage to the peak voltage. It is used to determine the value of flashover or puncture of insulation. Generally, the impulse ratio of the insulator is high.</u></em></h3>
3 0
2 years ago
Find the work done on a 50 Kg student by the elevator in 2 seconds, if the elevator is :
11Alexandr11 [23.1K]

The work done on a 50 Kg student by the elevator in 2 seconds if the elevator is accelerating upwards from rest at a rate of 2 ms⁻² would be

<h3>What is work done?</h3>

The total amount of energy transferred when a force is applied to move an object through some distance.

The work done is the multiplication of applied force with displacement.

Work Done = Force × Displacement

As given in the problem we have to find the work done  on a 50 Kg student by the elevator in 2 seconds if the elevator is  accelerating upwards from rest at a rate of 2 ms⁻²,

Lets us first calculate the displacement of the elevator in 2 seconds if it is accelerating upwards from rest at a rate of 2 ms⁻².

s = ut + 0.5at²

  = 0 + 0.5×2×2²

  = 4 meters

The work done on the elevator = mgh

                                                    =50×9.81×4

                                                    =1962 joules

Thus, the work done on the elevator would be 1962 joules.

To learn more about work done, refer to the link;

brainly.com/question/13662169

#SPJ1

5 0
1 year ago
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