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Masteriza [31]
3 years ago
6

Will mark as brainliest if correct!!!!!!!!

Physics
1 answer:
ArbitrLikvidat [17]3 years ago
7 0

Answer:

Light refracts when its speed changes as it enters a new medium.

Explanation:

Bending of light wave while it entering a medium with different speed is called refraction of light. Light passing from a faster medium to the slower medium bends the light rays toward the normal to boundary between two media. The amount of the  bending of light depends on refractive index of the two media which is described by  the Snell's Law. The angle of incidence is not equal to  angle of refraction. Rainbow is caused but this refraction phenomena. Also Refraction is used in magnifying glasses, prism and lenses

 

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A 1380 kg car starts from rest at the
Ulleksa [173]

Answer: 72200

Explanation:

First you must find the height for this is on an inclined hill using:

h=Lsin(angle) —> 28.0sin(11.0) = 5.34

Now you would just use the PE equation (mgh) because you are finding ME and when you starting from the top KE=0, showing that what ever answer you get from PE would equal the same for ME.

Using mgh:

m=1380

g=9.80

h=5.34

(1380)(9.8)(5.34)

=72218.16

*Rounding to the 3rd=72200

Hope this helps :)

6 0
2 years ago
an electron and a 0.0320-kg bullet each have a velocity of magnitude 510 m/s, accurate to within 0.0100%. within what lower limi
MArishka [77]

for this we apply, Heisenberg's uncertainty principle.

it states that physical variables like position and momentum, can never simultaneously know both variables at the same moment.

the formula is,

Δp * Δx = h/4π

m(e).Δv * Δx = h/4π

by rearranging,

Δx = h / 4π * m(e).Δv

Δx = (6.63*10^-34) / 4 * 3.142 * 9.11*10^-31 * 5.10*10^-2

Δx = 6.63*10^-34 / 583.9 X 10 ⁻³¹

Δx = 0.011 X 10⁻³

for the bullet

Δx = (6.63*10^-34) / 4 * 3.142 * 0.032*10^-31 * 5.10*10^-2

Δx = 6.63*10^-34 /2.05

Δx =3.23 X 10⁻³² m

therefore, we can say that the lower limits are   0.011 X 10⁻³  m for the electron and  3.23 X 10⁻³² m   for the bullet

To know more about bullet problem,

brainly.com/question/21150302

#SPJ4

6 0
1 year ago
Which image shows the correct way of lining up vectors to add them
Marina CMI [18]

Answer:

it's A

Explanation:

wen aligning the vectors the head and the tail should meet

4 0
1 year ago
A 1100 kg car rounds a curve of radius 68 m banked at an angle of 16 degrees. If the car is traveling at 95 km/h, will a frictio
Mariulka [41]

Answer:

Yes. Towards the center. 8210 N.

Explanation:

Let's first investigate the free-body diagram of the car. The weight of the car has two components: x-direction: towards the center of the curve and y-direction: towards the ground. Note that the ground is not perpendicular to the surface of the Earth is inclined 16 degrees.

In order to find whether the car slides off the road, we should use Newton's Second Law in the direction of x: F = ma.

The net force is equal to F = \frac{mv^2}{R} = \frac{1100\times (26.3)^2}{68} = 1.1\times 10^4~N

Note that 95 km/h is equal to 26.3 m/s.

This is the centripetal force and equal to the x-component of the applied force.

F = mg\sin(16) = 1100(9.8)\sin(16) = 2.97\times10^3

As can be seen from above, the two forces are not equal to each other. This means that a friction force is needed towards the center of the curve.

The amount of the friction force should be 8.21\times 10^3~N

Qualitatively, on a banked curve, a car is thrown off the road if it is moving fast. However, if the road has enough friction, then the car stays on the road and move safely. Since the car intends to slide off the road, then the static friction between the tires and the road must be towards the center in order to keep the car in the road.

5 0
3 years ago
A car drives 24 meters to the left in three seconds what is the velocity of the car?
sineoko [7]

Answer:

8 m/s to the left.

Explanation:

Applying,

V = d/t...................... Equation 1

Where V = Velocity of the car, d = distance, t = time

From the question,

Given: d = 24 meters, t = 3 seconds

Substitute these values into equation 1

V = 24/3

V = 8 m/s to the left.

Hence the velocity of the car is 8 m/s to the left.

5 0
3 years ago
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