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lakkis [162]
3 years ago
9

Refer to the following diagram to answer this question

Physics
2 answers:
svetoff [14.1K]3 years ago
7 0
In this case, the resistance for the diagram shown in the figure is located at point D. The symbol that best represents a resistance in an RLC diagram is one that is similar to that of point D.
 Also, remember that by definition V = I * R.
 The answer is D.
Sergeu [11.5K]3 years ago
6 0
The zig-zag line labeled ' D ' is the standard symbol for a resistor.
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Describing a Physical Change
babymother [125]

Answer:

physical change is the temporary change or riversible change here the physical properties r only changed

for example when water is cooled its get freezed Nd becomes ice similarly wen ice is heated again then it becomes water so here it's not changed permanently

I hope my ans is comprehensive

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6 0
2 years ago
An object is in circular motion. How will the object behave if the centripetal force is removed
stich3 [128]

The object will sail away in a straight line ... continuing in the same direction it was going when the centripetal force stopped.

3 0
3 years ago
1.) A stone falls from rest from the top of a cliff.
KengaRu [80]

Answer:

Explanation:

ignore air resistance

Let t be the time of fall for the dropped stone.

½(9.8)t² = 43.12(t - 2.2) + ½(9.8)(t - 2.2)²

4.9t² = 43.12t - 94.864 + 4.9(t² - 4.4t + 4.84)

4.9t² = 43.12t - 94.864 + 4.9t² - 21.56t + 23.716

     0 = 21.56t - 71.148

t = 71.148/21.56 = 3.3 s

h = ½(9.8)3.3² = 53.361 = 53 m

or

h = 43.12(3.3 - 2.2) + ½(9.8)(3.3 - 2.2)² = 53.361 = 53 m

4 0
2 years ago
If you started counting from 1st grade, how many years of education would the typical professional astronomer have today, at min
allochka39001 [22]

Answer:

16 years

Explanation:

I hope this helps.

4 0
2 years ago
Read 2 more answers
A light beam is traveling through an unknown substance. When it strikes a boundary between that substance and the air (nair≈1),
SashulF [63]

Answer:

0.7707

Explanation:

From Snell's law,

n(1) * sin θ1 = n(2) * sinθ2

Where n(1) = refractive index of air = 1.0003

θ1 = angle of incidence

n(2) = refractive index of second substance

θ2 = angle of refraction

The angle of reflection through the unknown substance is the same as the angle of incidence of air. Thus this means that θ1 = 29°

=> 1.0003 * sin29 = n(2) * sin39

n(2) = (1.0003 * sin29) / sin39

n(2) = 0.7707

Explanation:

6 0
3 years ago
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