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3 years ago

Will and Olly share £80 in the ratio 3:2 Work out how much each of them get

Mathematics

2 answers:

lesya [120]3 years ago

6 0

Answer:

£48 and £32

Step-by-step explanation:

sum the parts of the ratio, 3 + 2 = 5 parts

Divide £80 by 5 to find the value of one part of the ratio.

£80 ÷ 5 = £16 ← value of 1 part of the ratio, thus

3 parts = 3 × £16 = £48 ← Will

2 parts = 2 × £16 = £32 ← Olly

pav-90 [236]3 years ago

4 0

Will = £48

Olly =£ 32y

I hope it helps

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6. Suppose that a fair coin is tossed 2 times, and the result of each toss (H or T) is recorded.

nekit [7.7K]

Answer:

a) $S= {HH, HT, TH, TT}$

b) $P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25$

$P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5$

$P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25$

And we have the following table:

X | 0 | 1 | 2

P(X) | 0.25 | 0.5 | 0.25

Step-by-step explanation:

Let's define first some notation

H= represent a head for the coin tossed

T= represent tails for the coin tossed

We are going to toss a coin 2 times so then the size of the sample size is $2^2 = 4$

a. What is the sample space for this chance experiment?

The sampling space on this case is given by:

$S= {HH, HT, TH, TT}$

b. For this chance experiment, give the probability distribution for the random variable of the total number of heads observed.

The possible values for the number of heads are X=0,1,2. If we assume a fair coin then the probability of obtain heads is the same probability of obtain tails and we can find the distribution like this:

$P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25$

$P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5$

$P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25$

And we have the following table:

X | 0 | 1 | 2

P(X) | 0.25 | 0.5 | 0.25

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If a straight angel is bisected, what type of angels are the resulting angels

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Stels [109]

Answer:

Step-by-step explanation:

The diagram shows that the one triangle can be divided into two equal right triangles. Because of this, you can use the Pythagorean Theorem to solve this problem. a and b are the two sides of the angles, and c is the hypotenuse.

The given lengths are 5 as the hypotenuse and 3 as one length. (You have 3 as a given length because the two triangles have a length of 6 on one side. 6/2 = 3)

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