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Bumek [7]
3 years ago
8

If you need to do a 1:20 dilution on a culture to get acceptable plate counts, how many milliliters of original sample will you

add to a final volume of 0.1 mL?For this course, a 1:20 dilution is 1 part culture to a final volume of 20 parts.For example, 1 mL culture and 19 mL sterile DI water.Report your answer to 4 decimal places
Chemistry
1 answer:
aev [14]3 years ago
4 0

Answer:

0.0050 mL

Explanation:

First we <u>divide the final volume by 20</u>:

  • 0.1 mL / 20 = 0.005 mL

So if we add 0.005 mL of the original sample to 0.095 mL of sterile DI water, we're left with 0.1 mL of a 1:20 dilution.

Rounding up 0.005 mL to four decimal places, the answer thus is 0.0050 mL.

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<u>Answer:</u> The expression for equilibrium constant is K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}

<u>Explanation:</u>

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{eq}

For the general chemical equation:

aA+bB\rightleftharpoons cC+dD

The expression for K_c is given as:

K_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}

For the given chemical reaction:

2HgO(s)+H_2O(l)+2Cl_2(g)\rightleftharpoons 2HOCl(aq.)+HgO.HgCl_2(s)

The expression for K_{eq} is given as:

K_{eq}=\frac{[HOCl]^2[HgO.HgCl_2]}{[HgO]^2[H_2O][Cl_2]^2}

The concentration of solid is taken to be 0.

So, the expression for K_{eq} is given as:

K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}

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3 years ago
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