Answer:
6.43 moles of NF₃.
Explanation:
The balanced equation for the reaction is given below:
N₂ + 3F₂ —> 2NF₃
From the balanced equation above,
3 moles of F₂ reacted to produce 2 moles of NF₃.
Finally, we shall determine the number of mole of nitrogen trifluoride (NF₃) produced by the reaction of 9.65 moles of Fluorine gas (F₂). This can be obtained as follow:
From the balanced equation above,
3 moles of F₂ reacted to produce 2 moles of NF₃.
Therefore, 9.65 moles of F₂ will react to to produce = (9.65 × 2)/3 = 6.43 moles of NF₃.
Thus, 6.43 moles of NF₃ were obtained from the reaction.
The first option Forsure .
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Answer:
a) 0.925 mol Na2CO3 can be theoretically produced
b) 0.075 moles of the excess starting material remains
Explanation:
balaced chemical:
2 NaOH(s) + CO2(g) ↔ Na2CO3(s) + H2O(aq)
1.85n 1.00n Xn
moles theor. Na2CO3:
⇒ nNaCO3 = 1.85nNaOH * ( nNa2CO3 / 2nNaOH)
⇒ nNa2CO3 = 0.925nNa2CO3
moles of the excess:
⇒moles CO2 react = 1.85nNaOH * nCO2 / 2nNaOH = 0.925n CO2
⇒moles CO2 excess = 1.00n - 0.925n = 0.075n excess CO2
Answer:
Sulfur has the same amount, like all the other elements in group 16, has six valence electrons.
Explanation:
