The following amounts of water have not been listed.
However, to find m all you need to do it;
the amount of water which is in the tank - 124 = x
x ÷ 9 = m
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
Answer:
The answer is D
Step-by-step explanation:
Answer: 78
Step-by-step explanation:
2(l · w)
2(24·15)
78
![\sqrt[4]{\frac{6}{5}} = \sqrt[4]{b^4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B6%7D%7B5%7D%7D%20%3D%20%5Csqrt%5B4%5D%7Bb%5E4%7D)
![\sqrt[4]{\frac{6}{5}} = b](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B6%7D%7B5%7D%7D%20%3D%20b)
to predict how many bacteria will be present after 10 hours.![b = \sqrt[4]{\frac{6}{5}}](https://tex.z-dn.net/?f=b%20%3D%20%5Csqrt%5B4%5D%7B%5Cfrac%7B6%7D%7B5%7D%7D)
![A = 3000\sqrt[4]{\frac{6}{5}}^{10} = 4732.3228 = 4732](https://tex.z-dn.net/?f=A%20%3D%203000%5Csqrt%5B4%5D%7B%5Cfrac%7B6%7D%7B5%7D%7D%5E%7B10%7D%20%3D%204732.3228%20%3D%204732%20)