3 years ago

A fault in which the rocks on either side of the fault moves side of the fault move sideways past each other is a

2 answers:

8 0

California the San Andreas Fault. tensional-normal pulls rocks apart, compression-reverse the force that squeezes rocks together, shear-strike slip causes the rocks on either side of a fault to slide past each other. Waves generated by an earthquake that travels through the earth.

liberstina [14]3 years ago

3 0

It's called an earthquake

You might be interested in

What is Nuclear fusion

IRINA_888 [86]

Answer:

Nuclear fusion is a reaction in which two or more atomic nuclei are combined to form one or more different atomic nuclei and subatomic particles (neutrons or protons).

3 0

2 years ago

Green (Gg) Is crossed with a yellow pea plant (Gg )

Kobotan [32]

GG | Gg
-----------
Gg | gg

5 0

2 years ago

Read 2 more answers

Mr. Forester and Mr. Chavarin were cooking burgers at the Senior Picnic (this was pre-pandemic) and the propane grill ran out of

Varvara68 [4.7K]

Answer:

140

Explanation:

3 0

2 years ago

Which of the following is a valid conversion factor? (3 points)

Natali5045456 [20]

1,000 mL/ 1 L
Your last option

5 0

3 years ago

A certain substance X has a normal freezing point of 5.6 °C and a molal freezing point depression constant Kf-7.78 °C-kg·mol-1.

Harrizon [31]

Answer:

27.60 g urea

Explanation:

The freezing-point depression is expressed by the formula:

ΔT= Kf * m

In this case,

ΔT = 5.6 - (-0.9) = 6.5 °C

Kf = 7.78 °C kg·mol⁻¹

m is the molality of the urea solution in X (mol urea/kg of X)

First we calculate the molality:

6.5 °C = 7.78 °C kg·mol⁻¹ * m

m = 0.84 m

Now we calculate the moles of urea that were dissolved:

550 g X ⇒ 550 / 1000 = 0.550 kg X

0.84 m = mol Urea / 0.550 kg X

mol Urea = 0.46 mol

Finally we calculate the mass of urea, using its molecular weight:

0.46 mol * 60.06 g/mol = 27.60 g urea

7 0

3 years ago