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nasty-shy [4]
3 years ago
12

In the redox conversion of Ni2+ to NiO4−, the oxidation number of Ni goes from (−2, 0, +2) to (−1, +1, +7, +9). Recall that the

oxidation number of oxygen is typically −2.
1. 0; +9
2. +2; +7
3. +2; −1
4. −2; +9
5. −2; +7
6. 0; +1
7. 0; +7
8. +2; +9
9. −2; +1
Chemistry
1 answer:
inessss [21]3 years ago
7 0
Oxidation number of an atom is the charge that atom would have if the compound is composed of ions. In neutral substances that contains atoms of one element the oxidation number of an atom is zero. Thus atoms in O2, Ni2, and aluminium all have oxidation number of zero.
In this case, Ni2, the oxidation number of Ni atom is zero, 
for NiO4-, assuming oxidation number of Ni is x 
 (x ×1) + (-2 × 4) = -1
  x = + 7
Therefore, the oxidation number goes from 0 to +7
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Given a balanced chemical equation below: 3Cu(s) + 2H3PO4 --- > Cu3(PO4)2 + 3H2 How many moles of copper are needed to react
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Answer:

7.5 moles

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

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From the balanced equation above,

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4 0
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H_{2}SO_{4}(aq) + 2NaOH (aq) ----> Na_{2}SO_{4}(aq) + 2H_{2}O(l)

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ΔT is the temperature change = 31.50^{0}C - 21.45^{0}C = 10.05^{0}C

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Enthalpy of the reaction = \frac{6377 J*\frac{1kJ}{1000J}}{0.0506 mol} = 126 kJ/mol

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