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san4es73 [151]
3 years ago
15

The burning of gasoline to power internal combustion engines produces water vapor, and carbon dioxide gas that is thought to con

tribute to the "Greenhouse Effect" in the earth's atmosphere. Write the balanced chemical equation for burning gasoline (assume octane reacting with oxygen).
Chemistry
2 answers:
ser-zykov [4K]3 years ago
5 0

Answer:

the balanced equation to the combustion of gasoline is C8H18 + 12.5 O2 → 8 CO2 + 9 H2O (1)

frosja888 [35]3 years ago
4 0

Answer:

the equation of the octane and balanced combustion is as follows:

2C8H18 + 25O2 = 16CO2 + 18H2O

Explanation:

Octane combustion is a chemical chain reaction, producing heat.

The spark-ignited combustion engine transforms the thermal energy from the combustion of gasoline plus air into motive energy. The combustion of gasoline is preceded by the formation of gasoline and air in the carburettor, this mixture enters the cylinder through the supply system, then is compressed by the upward stroke of the piston and then inflamed by the spark. Due to combustion, the volume of the mixture increases rapidly, creating a strong pressure that moves the piston.

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How many covalent bonds are predicted for each atom: (a) F; (b) Si; (c) Br; (d) O; (e) P; (f) S?
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The <span>covalent bonds are predicted for each atom are :

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6 0
3 years ago
Although both N2 and 02 are naturally present in the air we breathe, high levels of NO and NO2 in the atmosphere occur mainly in
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Answer:

(a) Increasing the temperature adds heat which is a reactant shifting the equilibrium rightwards.

(b) Pressure has no effect since the change in the number of moles is zero.

Explanation:

Hello,

In this case, one could represent the given reaction as:

N_2(g)+O_2(g)+ \Delta _rH \leftrightarrow 2NO

Since it is endothermic. Thus, solving the (a) statement, one identifies the heat as a reagent, that is why the reaction cools down as it progress, therefore, by increasing the temperature, heat is added, that is, a reagent is added, which shifts the equilibrium rightwards, in other words, more NO is produced so its concentration increases.

Furthermore, for the (b) statement, since the change in the number of moles is zero, based on the stoichiometric coefficients as shown below:

\Delta \nu =2-1-1=0

Such value implies that the pressure has no effect on the concentration, taking into account the following form of the law of mass action:

Kp=Kc(RT)^{\Delta \nu }

Thus, since \Delta \nu =0, Kp=Kc, so no effect in concentration is due to the pressure.

Best regards.

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