Answer:
75L of additional water to have a pH 1 solution
Explanation:
The reaction of HCl With NaOH is:
HCl + NaOH → H₂O + NaCl
By using molar mass of each reactant you can know how many moles will react, thus:
HCl: 364.6g HCl ₓ (1mol / 36.46g) = 10 moles HCl
NaOH: 80g NaOH ₓ (1mol / 40g) = 2 moles NaOH
That means after the reaction will remain in solution, 10-2 = 8 moles of HCl = 8 moles of H⁺ (In water, HCl dissociates as H⁺ and Cl⁻ ions).
A solution with pH = 1 contains:
pH = -log [H⁺]
1 = -log [H⁺]
0.1M = [H⁺]
As molarity, M is the ratio between moles and liters and you want a solution 0.1M having 8 moles of H⁺ you require:
0.1M = 8 moles H⁺ / 80L
As the student combines the solution with 5L of water, you require
<h3>75L of additional water to have a pH 1 solution</h3>
