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miss Akunina [59]
3 years ago
15

How many degrees of unsaturation are lost or gained in the base-induced transformation from mito-ph to its photoactive ring-open

ed form?
Chemistry
1 answer:
Fudgin [204]3 years ago
6 0

Unsaturation (IHD) 2 hydrogen Needed

IHD = [(2n+2) -H]/2
(H: X=1, N=-1, O= zero)

Unsaturation:
Double bonds = 1
Rings = 1
Triple Bonds = 2

The degrees of unsaturation in a molecule are additive — a molecule with one double bond has one degree of unsaturation, a molecule with two double bonds has two degrees of unsaturation, and so forth.



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How many grams of a stock solution that is 92.5 percent H2SO4 by mass would be needed to make 250 grams of a 35.0 percent by mas
IrinaVladis [17]

94.6 g.  You must use 94.6 g of 92.5 % H_2SO_4 to make 250 g of 35.0 % H_2SO_4.

We can use a version of the <em>dilution formula</em>

<em>m</em>_1<em>C</em>_1 = <em>m</em>_2<em>C</em>_2

where

<em>m</em> represents the mass and

<em>C</em> represents the percent concentrations

We can rearrange the formula to get

<em>m</em>_2= <em>m</em>_1 × (<em>C</em>_1/<em>C</em>_2)

<em>m</em>_1 = 250 g; <em>C</em>_1 = 35.0 %

<em>m</em>_2 = ?; _____<em>C</em>_2 = 92.5 %

∴ <em>m</em>_2 = 250 g × (35.0 %/92.5 %) = 94.6 g

4 0
3 years ago
how many grams of potassium chloride, KCL(molar mass is 74.55g/mol) are produced if 25 grams of potassium chlorate KClo^3 decomp
JulsSmile [24]

Answer:

                     Mass = 15.20 g of KCl

Explanation:

                    The balance chemical equation for the decomposition of KClO₃ is as follow;

                                            2 KClO₃ = 2 KCl + 3 O₂

Step 1: Calculate moles of KClO₃ as;

Moles = Mass / M/Mass

Moles = 25.0 g / 122.55 g/mol

Moles = 0.204 moles

Step 2: Find moles of KCl as;

According to equation,

                  2 moles of KClO₃ produces  =  2 moles of KCl

So,

               0.204 moles of KClO₃ will produce  =  X moles of KCl

Solving for X,

                       X = 2 mol × 0.204 mol / 2 mol

                       X = 0.204 mol of KCl

Step 3: Calculate mass of KCl as,

Mass = Moles × M.Mass

Mass = 0.204 mol × 74.55 g/mol

Mass = 15.20 g of KCl

6 0
3 years ago
Q 9 The table lists the steps to clean water for drinking purpose. 1. Adding chlorine tablets to the water.2. Pouring the water
love history [14]

Answer:

1 and 2

Explanation:

when we r adding chlorine to water

the water is clean

8 0
3 years ago
24 g of magnesium were burned in oxygen. The compound formed had a mass of 40 g. Explain why the mass had gone up.
DIA [1.3K]

Answer :

According to the law of conservation of mass, the mass of reactants must be equal to the mass of products.

The balanced chemical reaction is,

Mg+\frac{1}{2}O_2\rightarrow MgO

As we know that the molar mass of magnesium is 24 g/mole, the molar mass of O_2 is 32 g/mole and the molar mass of magnesium oxide is 40 g/mole.

From the given balanced reaction, we conclude that

As, 1 mole of magnesium react \frac{1}{2} mole of oxygen to give 1 mole of magnesium oxide.

So, the mass of Mg is 24 g, the mass of O_2=\frac{1}{2}\times 32=16g and the mass of MgO is 40 g.

That means 24 g of Mg react with 16 g O_2 to give 40 g of MgO.

8 0
3 years ago
Why is this image a good model for the Law of Conservation of Mass?
ZanzabumX [31]

Answer:

The Law of Conservation of Mass states that mass is neither created nor destroyed in chemical reactions. Since the number and type of atoms in the reactant side of the chemical equation are the same as on the product side, the Law of Conservation of Mass has been demonstrated.

Explanation:

In the answer.

8 0
3 years ago
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