What is -12.6 as a simplified percent?

3. Alyssa has to make 70 pancakes, how many cups of flour will she have to use?

Sonbull [250]

Answer:

14 cups

Step-by-step explanation:

3 0

3 years ago

Whats the median number mode and mean for 95, 97, 100, 86, 78, 96

Naya [18.7K]

Answer:

Mean = 92

Median = 95.5

There is no mode.

What is mean, median, and mode?

Mean, median, and mode are terms in math when it comes to looking at charts and sets/groups of numbers.

1. The mean is the average of a data set.

2. The median is the middle of a data set.

3. The mode is the most common number in a data set.

Mean is found by adding the numbers and dividing the sum by the number of numbers in the list. This is what is most often meant by an average. The median is the middle value in a list ordered from smallest to largest. The mode is the most frequently occurring value on the list.

Before we start, let's put the set of numbers in order from least to greatest,

95, 97, 100, 86, 78, 96

78, 86, 95, 96, 97, 100

Now that we have done that let's find the mean,

78 + 86 + 95 + 96 + 97 + 100 = 552

There are 6 numbers in this set so we need to divide 552 by 6,

552 ÷ 6 = 92

92 is the mean/average of this data set,

Now let's find the median,

If we take a look at the data set we can see that there are two numbers in the middle because there are 6 in total,

78, 86, 95, 96, 97, 100

Because there are two values that are in the middle we need to add them up and divide the sum of them by 2,

95 + 96 = 191

191 ÷ 2 = 95.5

95.5 is the median of this data set,

Now let's find the mode,

If we take a look at the date set we can see that none of the numbers are repeated,

So this means there is no mode to this data set,

Therefore the mean is 92, the median is 95.5, and there is no mode.

4 0

2 years ago

If the radius is 14cmand The perimeter of the sector is 57.32cm.<br>what is the size of the angle?

Degger [83]

Answer:

120°

Step-by-step explanation:

A sector of a circle is the portion or region of a circle enclosed by two radii and an arc. The perimeter of a the sector of a circle is given by the formula:

Perimeter of sector = $\frac{\theta}{360} *2\pi r$ + 2r

Where θ is the angle which forms the sector and r is the radius of the circle.

Given that Perimeter of sector = 57.32 cm, radius (r) = 14 cm, we can find the angle θ using:

Perimeter of sector = $\frac{\theta}{360} *2\pi r$ + 2r

$57.32=\frac{\theta}{360} *2\pi *14+2(14)\\\\57.32-28=\frac{\theta}{360} *2\pi *14\\\\29.32=\frac{\theta}{360} *2\pi *14\\\\ \frac{\theta}{360}=\frac{29.32}{2\pi *14} \\\\\frac{\theta}{360}=0.33\\\\\theta=120^o$

7 0

3 years ago

Enter an inequality that represents the description, and then solve.

natta225 [31]

Answer:

X >= 7

Step-by-step explanation:

7x + 8 >= 57

7x >= 57-8

7x >= 49

x >= 49/7

x >= 7

5 0

3 years ago

A Survey of 85 company employees shows that the mean length of the Christmas vacation was 4.5 days, with a standard deviation of

GenaCL600 [577]

Answer:

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

Step-by-step explanation:

We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 85 - 1 = 84

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 1.989.

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 1.989\frac{1.2}{\sqrt{85}} = 0.26$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

92% confidence interval:

Following the sample logic, the critical value is 1.772. So

$M = T\frac{s}{\sqrt{n}} = 1.772\frac{1.2}{\sqrt{85}} = 0.23$

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

8 0

3 years ago