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natita [175]
4 years ago
8

a very thin layer of gold plating was placed on a metal tray that measures 25.22 cm by 13.22cm. The gold plating increased the m

ass of the plate by 0.0512 g. Calculate the thickness of the plating. The density of gold is 19.31 g/cm ^3
Physics
1 answer:
marshall27 [118]4 years ago
5 0
<span>As the volume of gold is 

Volume = mass/ density 

V = </span>0.0512g / 19.31gcm^−3
=0.0026

Volume of gold = L. W. T
0.0026 = 52.22 * 13.22 * T
Thickness T = 0.0026 / 690.43

T= 3.7 * 10^-6

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A roller-coaster car has a mass of 1040 kg when fully loaded with passengers. As the car passes over the top of a circular hill
rusak2 [61]

Answer:

a.6373.5 N

b.-3837.6 N

Explanation:

Mass of roller coaster=m=1040 kg

Radius=r=24 ,

a.v=9.4m/s

Normal force=F_N

According to question

mg-F_N=\frac{mv^2}{r}

Where g=9.81 m/s^2

Substitute the values

1040\times 9.81-F_N=\frac{1040\times (9.4)^2}{24}

10202.4-F_N=3828.9

F_N=10202.4-3828.9=6373.5 N

b.v=18m/s

g=9.81 m/s^2

1040\times 9.81-F_N=\frac{1040\times (18)^2}{24}

10202.4-F_N=14040

F_N=10202.4-14040=-3837.6 N

8 0
4 years ago
A person walks 1 mile every day for exercise, leaving her front porch at 9:00 am. and returning to her front porch at 9:25 am. W
Alexxx [7]

Answer: 0

Explanation:

Given that:

Distance walked per day = 1 mile

Starting position = front of house

Final position = front of house(initial position).

In other to aid understanding; Displacement simply refers to the shortest or least distance measured from an individual's initial position to his final point.

Here,

Assume, front of house = point A

Then , initial position = point A (front of house)

Final position, = point A (front of house)

Hence, the shortest distance between final and initial positions is :

Point A - Point A = 0

Since, starting point is the same as the final point, then Displacement = 0

5 0
3 years ago
Expectant mothers many times see their unborn child for the first time during an ultrasonic examination. In ultrasonic imaging,
Rzqust [24]

A) A. 380 kHz

To clerly see the image of the fetus, the wavelength of the ultrasound must be 1/4 of the size of the fetus, therefore

\lambda=\frac{1}{4}(1.6 cm)=0.4 cm=0.004 m

The frequency of a wave is given by

f=\frac{v}{\lambda}

where

v is the speed of the wave

\lambda is the wavelength

For the ultrasound wave in this problem, we have

v = 1500 m/s is the wave speed

\lambda=0.004 m is the wavelength

So, the frequency is

f=\frac{1500 m/s}{0.004 m}=3.75\cdot 10^5 Hz=375 kHz \sim 380 kHz

B) B. f(c+v)/c−v

The formula for the Doppler effect is:

f'=\frac{v\pm v_r}{v\pm v_s}f

where

f' is the apparent frequency

v is the speed of the wave

v_r is the velocity of the receiver (positive if the receiver is moving towards the source, negative if it is moving away from the source)

v_s is the speed of the source (positive if the source is moving away from the receiver, negative if it is moving towards the receiver)

f is the original frequency

In this problem, we have two situations:

- at first, the ultrasound waves reach the blood cells (the receiver) which are moving towards the source with speed

v_r = +v (positive)

- then, the reflected waves is "emitted" by the blood cells (the source) which are moving towards the source with speed

v_s = -v

also

v = c = speed of sound in the blood

So the formula becomes

f'=\frac{c + v}{v - v_s}f

C. A. The gel has a density similar to that of skin, so very little of the incident ultrasonic wave is lost by reflection

The reflection coefficient is

R=\frac{(Z_1 -Z_2)^2}{(Z_1+Z_2)^2}

where Z1 and Z2 are the acoustic impedances of the two mediums, and R represents the fraction of the wave that is reflected back. The acoustic impedance Z is directly proportional to the density of the medium, \rho.

In order for the ultrasound to pass through the skin, Z1 and Z2 must be as close as possible: therefore, a gel with density similar to that of skin is applied, in order to make the two acoustic impedances Z1 and Z2 as close as possible, so that R becomes close to zero.

3 0
3 years ago
You're standing in a large room when a loud noise is made and you hear a series of echoes. Which characteristi
MrMuchimi
The correct answer is Reverberation (C)
4 0
2 years ago
Threshold potential refers to the membrane potential required to:
ivanzaharov [21]

B. initiate an action potential.

Action potentials are initiated when a depolarization reaches a threshold potential. This threshold potential varies, but is normally around 55 or 50 millivolts above the resting potential of the cell, which implies that the input current of sodium ions exceeds the output current of potassium ions.

4 0
3 years ago
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