12 is what percent of 96

katie collected 470 cans the first week of the school project. The second week she collected 105 less than the first week. How m

valentinak56 [21]

Answer:

Katie collected 365 cans in the second week.

Step-by-step explanation:

Because Katie collected 470 cans in the first week, and 105 less in the second week, we know to subtract 105 from 470, which gives us 365 cans.

8 0

3 years ago

Graph the image of this figure after a dilation with a scale factor of 3 centered at (-7,-6)

Yuri [45]

Given that the triangle is dilated by factor 3, the image will be found as follows;
The object is at:
A(-7,-3), B(-3,-2), C(-4,-5)
when the image was enlarged the new coordinates will be:
A'=3(-7,-3)=(-21,-9)
B'=3(-3,-2)=(-9,-6)
C'=3(-4,-5)=(-12,-15)
since the image is centered at the point (-7,-6), the final point will be at:
A"=[(-21+-7),(-9+-6)=(-28,-15)
B''=[(-9+-7),(-6+-6)]=(-16,-12)
C''=[(-12+-7),(-15+-6)]=(-19,-17)
thus the coordinates of the final image are:
A''(-28,-15),B''(-16,-12),C''(-19,-17)

3 0

3 years ago

If 75% of an iceberg's height is hidden below the surface of the water, what is the total height of

Illusion [34]

Answer:

1800

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The American Bankers Association reported that, in a sample of 120 consumer purchases in France, 48 were made with cash, compare

tatuchka [14]

Answer:

Step-by-step explanation:

Hello!

You have the information for two variables

X₁: Number of consumer purchases in France that were made with cash, in a sample of 120.

n₁= 120 consumer purchases

x₁= 48 cash purchases

p'₁= 48/120= 0.4

X₂: Number of consumer purchases in the US that were made with cash, in a sample of 55.

n₂= 55 consumer purchases

x₂= 24 cash purchases

p'₂= 24/55= 0.4364

You need to construct a 90% CI for the difference of proportions p₁-p₂

Using the central limit theorem you can approximate the distribution of both sample proportions p'₁ and p'₂ to normal, so the statistic to use to estimate the difference of proportions is an approximate standard normal:

[(p'₁-p'₂) ± $Z_{1-\alpha /2}$ * $\sqrt{\frac{p'_1(1-p'_1)}{n_1} +\frac{p'_2(1-p'_2)}{n_2} }$ ]

$Z_{0.95}= 1.648$

[(0.4-0.4364)±1.648 * $\sqrt{\frac{0.4(1-0.4)}{120} +\frac{0.4364(1-0.4364)}{55} }$ ]

[-0.1689;0.0961]

The interval has a negative bond, it is ok, keep in mind that even tough proportions take values between 0 and 1, in this case, the confidence interval estimates the difference between the two proportions. It is valid for one of the bonds or the two bonds of the CI for the difference between population proportions to be negative.

I hope this helps!

8 0

3 years ago

Which of these graphs represents the inequality x <10

PtichkaEL [24]

Answer:

There are no graphs, but the graph should look lyke this:

An open circle on the point "10"

And from the 10, the arrow should be going left, towards the negatives, or smaller numbers than the ten

8 0

2 years ago