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3 years ago

Loudness is expressed in

Chemistry

2 answers:

Alex787 [66]3 years ago

8 0

Answer:

Waves

Explanation:

Archy [21]3 years ago

6 0

Answer:

Decibel

Explanation:

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On which of the following objects will the earth exert a greater gravitational pull than on a baseball?

dem82 [27]

Answer:

Explanation: brainliest

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3 years ago

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A 101.2 ml sample of 1.00 m naoh is mixed with 50.6 ml of 1.00 m h2so4 in a large styrofoam coffee cup; the cup is fitted with a

Murrr4er [49]

The enthalpy change of the reaction when sodium hydroxide and sulfuric acid react can be calculated using the mass of solution, temperature change, and specific heat of water.

The balanced chemical equation for the reaction can be represented as,

$H_{2}SO_{4}(aq) + 2NaOH (aq) ----> Na_{2}SO_{4}(aq) + 2H_{2}O(l)$

Given volume of the solution = 101.2 mL + 50.6 mL = 151.8 mL

Heat of the reaction, q = $m C .$ Δ $T$

m is mass of the solution = 151.8 mL * $\frac{1 g}{1 mL} = 151.8 g$

C is the specific heat of solution = 4.18 $\frac{J}{g. ^{0}C}$

ΔT is the temperature change = $31.50^{0}C - 21.45^{0}C = 10.05^{0}C$

q = $151.8 g (4.18 \frac{J}{g ^{0}C})(10.05^{0}C) = 6377 J$

Moles of NaOH = $101.2 mL * \frac{1L}{1000 mL}*\frac{1.00 mol}{L} = 0.1012 mol$ NaOH

Moles of $H_{2}SO_{4}$ = $50.6 mL * \frac{1 L}{1000 mL} * \frac{1.0 mol}{1 L} = 0.0506 mol H_{2}SO_{4}$

Enthalpy of the reaction = $\frac{6377 J*\frac{1kJ}{1000J}}{0.0506 mol} = 126 kJ/mol$

5 0

3 years ago

What is the wavelength of light with 2.89 x 10-19 J of energy? (The speed of

Alika [10]

Let's see

$\\ \rm\rightarrowtail E=hv$

$\\ \rm\rightarrowtail E=\dfrac{hc}{\lambda}$

lambda is wavelength
h is Planck constant
c is velocity of sound in air
E in energy

$\\ \rm\rightarrowtail \lambda=\dfrac{hc}{E}$

$\\ \rm\rightarrowtail \lambda=\dfrac{6.626\times 10^{-34}\times 3\times 10^8}{2.89\times 10^{-19}}$

$\\ \rm\rightarrowtail \lambda=6.878\times 10^{-7}m$

$\\ \rm\rightarrowtail \lambda=68.8\mu m$

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2 years ago

What is the density of an 84.7 g sample of an unknown substance if the sample occupies 49.6cm cubed

Ahat [919]

Answer:

1.70 g.cm⁻³

Solution:

Data Given;

Mass = 84.7 g

Volume = 49.6 cm³

Density = ?

Formula Used;

Density = Mass ÷ Volume

Putting values,

Density = 84.7 g ÷ 49.6 cm³

Density = 1.70 g.cm⁻³

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3 years ago

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