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sesenic [268]
3 years ago
12

Vitellium (Vi) has the following composition:

Chemistry
1 answer:
Dvinal [7]3 years ago
4 0
Answer is: <span>C.)It will be closer to the mass of Vi–193.
</span><span>Average atomic mass of vitellium =
Ar(Vi-188) </span>· ω(Vi-188) + Ar(Vi-191) · ω(Vi-191) + Ar(Vu-193) · ω(Vi-193).
Average atomic mass of vitellium = 
187.9122 amu · 0,10861 + 190.9047 amu · 0,12428 + 192.8938 amu · 0,76711.
Average atomic mass of vitellium = 20,409 + 23,725 + 147,970.
Average atomic mass of vitellium = 192,104.
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can someone help me with these? I just started chemistry this semester, and since it's involving math I don't see myself doing g
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Any non zero digits are significant. (120 has 2 sig figs)

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Zeroes only count if there is a decimal point and if they are following a significant digit. (.600 has 3 sig figs; .067 has 2 sig figs)

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That's all I'm gonna do so yeah.

Now for the rounding, it's basically rounding but it must have the x amount of sig figs after rounding. It's pretty hard to explain.

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20) 5.457, alright so here, since we are rounding to three significant digits, we look at the third sig fig. The third sig fig here would be 5. Then we just round. Since the number next to 5 is 7, we round 5 up to 6.

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2 years ago
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