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sesenic [268]
3 years ago
12

Vitellium (Vi) has the following composition:

Chemistry
1 answer:
Dvinal [7]3 years ago
4 0
Answer is: <span>C.)It will be closer to the mass of Vi–193.
</span><span>Average atomic mass of vitellium =
Ar(Vi-188) </span>· ω(Vi-188) + Ar(Vi-191) · ω(Vi-191) + Ar(Vu-193) · ω(Vi-193).
Average atomic mass of vitellium = 
187.9122 amu · 0,10861 + 190.9047 amu · 0,12428 + 192.8938 amu · 0,76711.
Average atomic mass of vitellium = 20,409 + 23,725 + 147,970.
Average atomic mass of vitellium = 192,104.
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In the given examples we have:

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126.0g of water were initially present

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<em />

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<em>Moles Oxygen:</em>

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Based on the chemical equation, the moles of water initially present were 7 moles (That produce 7 moles H₂ and 3.5 moles O₂). The mass of 7 moles of H₂O is:

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<h3>126.0g of water were initially present</h3>
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