The name of the compound PbS2.4H2O would be hydrate of Lead(IV) sulfide. <span>The IV is to show that the lead in the </span>compound<span> has an oxidation state of +4. Lead also has an oxidation state of +2. Hope this answers the question. Have a nice day.</span>
Explanation: In IUPAC, E-Z convention is given for describing the cis - trans notation to the isomers. According to CIP rule, the groups on the doubly bonded carbon atoms are given priorities based on the the atomic masses of first connected atom.
If the highest priority groups are on the same side, it is known as Z-form and if the highest priority groups are on opposite side, it is known as E-form.
We are given (Z)-3-bromo-6-methyl-2-heptene, in this the highest priority groups are bromine on one side and methyl- group on another side.
The structure is provided in the image below.
1 mole H2O ---------------------- 6.02x10²³ molecules
4 moles H2O--------------------- y molecules
y = 4 * 6.02x10²³
y = 2.4x10^24 molecules
answer b
hope this helps!.
Answer:
Changing the surface area from minimum to maximum increases the number of reactants in a chemical reaction.
An increase in surface area of a solid reactant means more of its particles are exposed to attack by the other Particle. This results in an increased chance of collisions between reactant particles, so there are more collisions in any given time and the rate of reaction increases.
The correct answer to the question you’ve asked would be false
