Part A)<span>In a 45-45-90 triangle, what is the length of the hypotenuse when the length of one of the legs is 11 in.?
we know that
</span>cos 45°=√2/2
[he length of the hypotenuse]=11/cos 45-----------> 11/(√2/2)----> (11*2)/√2
=22/√2-------> 11√2 in
the answer Part A) is 11√2 in
Part B) <span>What is the exact value of sin 45° ?
</span>
we know that
sin 45°=11/(11√2)-------> 1/√2---------> (1/√2)*(√2/√2)-----> √2/2
the answer part b) is √2/2
Part C)
<span>What is the area of a regular hexagon with a side length of 4 m?
we know that
</span>In case of a regular hexagon <span> each of the six triangles that are formed by connecting its center with all six vertices is an equilateral triangle with a side equaled to 4 m.
The area of this hexagon is six times greater than the area of such a triangle
</span>
In an equilateral triangle with a side d<span>
the altitude </span>h can be calculate from the Pythagorean Theorem as
h²=d²−(d/2)²=(3/4)d²
<span>Therefore,
</span><span>h=d<span>√3/2
</span></span><span>Area of such a triangle is
</span>A=d*h/2------------> d²*√3/4
From this the area of the regular hexagon with a side d<span> is
</span>S=6*A----------> d²3√3/2
for d=4 m
S=4²3√3/2------> 24√3 m²------------> 41.57 m²
the answer Part C) is 41.57 m²
Part D) <span>In a 30-60-90 triangle, what is the length of the hypotenuse when the shorter leg is 5 cm?
</span>[he length of the hypotenuse]=5/sin 30--------> 5/(1/2)---------> 10 cm
the answer part D) is 10 cm
Answer: 492150064
Step-by-step explanation:
Answer:
7.9 ft
Step-by-step explanation:
The hypotenuse is the side opposite of the right angle, hence the hypotenuse for this triangle is 11 ft.
Side
is adjacent to the angle given. So we need adjacent and we have hypotenuse. Which trigonometric ratio relates adjacent and hypotenuse? It is COSINE.
<em>Thus, we can write:</em>

<em>Cross multiplying, we can solve for
:</em>

Rounding to nearest tenth, we have
ft.
A. graph. 1.2 because dm me let me see the worksheet
Answer:
Thanks kind stranger! :)
Step-by-step explanation: