All categories

3 years ago

In the diagram below, point M is the midpoint of line JK. What are the coordinates of point J.

Mathematics

2 answers:

mariarad [96]3 years ago

6 0

The diagram isn’t there not

Marrrta [24]3 years ago

5 0

The last option . A midpoint’s coordinate equals 1/2 multiply the left plus the right

You might be interested in

Would a teaspoon be a good way to measure the capacity of a milk carton? Explain.

ohaa [14]

No teaspoon would take forever if you want though but you can use this instead quarts it's way easier oh and 1 gallon is 4 quarts hoped this helped.

4 0

3 years ago

Help me with this please

Elenna [48]

Answer:

2,700 sq yds :)))) (d)

Step-by-step explanation:

2(30)=60

1.5(30) =45

60(45)= 2700

3 0

3 years ago

Put 18/45 in simplest form

Nesterboy [21]

Okay so 18/45 = 2/5 in simplest form. hope this helped

4 0

3 years ago

Read 2 more answers

What's your real rate of return if your savings account pays 2.5% interest and inflation is at 1%?

kolbaska11 [484]

Answer:

Real rate of return = 1.5%

Step-by-step explanation:

Given:

Savings account return = 2.5%

Inflation rate = 1%

Find:

Real rate of return = ?

Computation:

⇒ Nominal rate of return = Real rate of return + Inflation rate

⇒ Real rate of return = Savings account return - Inflation rate

⇒ Real rate of return = 2.5% - 1%

⇒ Real rate of return = 1.5%

6 0

3 years ago

A gondola (cable car) at a ski area holds 50 people. Its maximum safe load is 10000 pounds. A population of skiers has a distrib

fenix001 [56]

Answer: 0.03855

Step-by-step explanation:

Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.

Its maximum safe load is 10000 pounds.

Let X denotes the weight of 50 people.

As per given ,

Population mean weight of 50 people = $\mu=50\times190=9500\text{ pounds}$

Standard deviation of 50 people $=\sigma=40\sqrt{50}=40(7.07106781187)=282.84$

Then , the probability its maximum safe load will be exceeded =

$P(X>10000)=P(\dfrac{X-\mu}{\sigma}>\dfrac{10000-9500}{282.84})\\\\=P(z>1.7671-8)\\\\=1-P(z\leq1.7678)\ \ \ \ [\because\ P(Z>z)=P(Z\leq z)]\\\\=1-0.96145\ \ \ [\text{ By p-value of table}]\\\\=0.03855$

Thus , the probability its maximum safe load will be exceeded = 0.03855

3 0

3 years ago