Answer:
A. 0.0450
B. 4
C. 0.25
D. 37.68
E. 6Hz
F. -0.523
G. 1.5m/s
H. vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)
I. -1.67m/s.
Explanation:
Given the equation:
y(x,t) = 0.0450 sin(25.12x - 37.68t-0.523)
Standard wave equation:
y(x, t)=Asin(kx−ωt+ϕ)
a.) Amplitude = 0.0450
b.) Wave number = 1/ λ
λ=2π/k
From the equation k = 25.12
Wavelength(λ ) = 2π/25.12 = 0.25
Wave number (1/0.25) = 4
c.) Wavelength(λ ) = 2π/25.12 = 0.25
d.) Angular frequency(ω)
ωt = 37.68t
ω = 37.68
E.) Frequency (f)
ω = 2πf
f = ω/2π
f = 37.68/6.28
f = 6Hz
f.) Phase angle(ϕ) = -0.523
g.) Wave propagation speed :
ω/k=37.68/25.12=1.5m/s
h.) vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)
(i) vy(3.5m, 21s) = 0.045(-37.68) cos (25.12*3.5-37.68*21-0.523) = -1.67m/s.
Answer:
#include <bits/stdc++.h>
using namespace std;
void funct(){
string name;
cout<<"enter the string: ";
cin>>name;
reverse(name.begin(), name.end());
cout<<"The string is : "<<name<<endl;
}
int main()
{
funct();
return 0;
}
Explanation:
create the function funct() with return type void and declare the variable type string and print a message for asking to used enter the string.
The string enter by user is store in the variable using cin instruction.
after that, we use a inbuilt function reverse() which takes two argument.
firs argument tell the starting point and second index tell the ending point. then, the reverse function reverse the string.
name.begin() it is a function which return the pointer of first character of string.
name.end() it is a function which return the pointer of last character of the string.
finally, print the reverse string.
for calling the function, we have to create the main function and then call the function.
I believe in this case you would be using Clip Art.
Smart Art is used on words to make graphics usually.
Graphs are not pictures
Shapes are completely different
I would say the answer is b, but ⟟ might be wrong
