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yuradex [85]
3 years ago
10

How can you increase the strength of an electromagnet?

Physics
1 answer:
densk [106]3 years ago
4 0

1) Increasing the current flow


2) Increasing the number of coils


3) Passing an 'iron core' through the coil of the electromagnet

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Through what vertical height is a 50 N object moved if 250 J of work is done lifting it against the gravitational field of Earth
zimovet [89]

5m

Explanation:

Given parameters:

Weight of object = 50N

Work done in lifting object = 250J

Unknown:

Vertical height = ?

Solution:

The work done on an object is the force applied to lift a body in a specific direction.

   Work done = force x distance

  Weight is a force in the presence of gravity;

  Work done = weight x height of lifting

Height of lifting = \frac{work done }{weight}

 Height of lifting = \frac{250}{50} = 5m

The vertical height through which the object was lifted is 5m

learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

6 0
3 years ago
In tokyo ghoul book 2 who is the main character and who taught ken kaneki the kagune
Inessa05 [86]

Answer:by book 2 do you mean the original or re, if you you mean who taught kaneki to control his kagune it was yoshimura (the manager) but if your talking about how to fight with control of his kagune its was Yomo

Explanation: if I'm wrong correct me and i'll do more research

3 0
3 years ago
Read 2 more answers
What is a main difference between Mars and Saturn?
tiny-mole [99]

Answer:

2

Explanation:

mars has a shorter year because when it revolves around the sun, it takes less time than, saturn who is millions of miles away from mars, longer. Also, mars is closer to the sun than saturn

8 0
3 years ago
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Which of these results in kinetic energy of an object? position motion mass volume
Ray Of Light [21]

Answer:

motion

Explanation:

the motion causes static which is kinetic energy

3 0
3 years ago
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The electric field everywhere on the surface of a thin, spherical shell of radius 0.770 m is of magnitude 860 N/C and points rad
11111nata11111 [884]

Answer:

(a) Q = 7.28\times 10^{14}

(b) The charge inside the shell is placed at the center of the sphere and negatively charged.

Explanation:

Gauss’ Law can be used to determine the system.

\int{\vec{E}} \, d\vec{a} = \frac{Q_{enc}}{\epsilon_0}\\E4\pi r^2 = \frac{Q_{enc}}{\epsilon_0}\\(860)4\pi(0.77)^2 = \frac{Q_{enc}}{8.8\times 10^{-12}}\\Q_enc = 7.28\times 10^{14}

This is the net charge inside the sphere which causes the Electric field at the surface of the shell. Since the E-field is constant over the shell, then this charge is at the center and negatively charged because the E-field is radially inward.

The negative charge at the center attracts the same amount of positive charge at the surface of the shell.

5 0
3 years ago
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