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3 years ago

A sound wave traveling eastward through air

Physics

2 answers:

Sholpan [36]3 years ago

6 0

Answer : A sound wave traveling eastward through air causes the air molecules to vibrate east and west

Explanation :

We know that the sound wave is a longitudinal wave. The particles of medium travels in the direction of propagation of the wave. The space where the particles are closely spaced is called compression and the space where the particles are far apart is called rarefaction. Also, the distance between two consecutive compression and rarefaction is called the wavelength.

If the sound wave is travelling in eastward direction, then the air molecules will move in the direction of propagation of wave. They will vibrate either in east or west direction.

So, the correct option is (1) " vibrate east and west ".

Wewaii [24]3 years ago

5 0

A sound wave traveling eastward through air<span> causes the air molecules to Vibrate east and west. </span>

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Vsevolod [243]

Answer:

It looks like the second one is the correct answer.

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3 years ago

Read 2 more answers

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Shtirlitz [24]

Answer:

D) D = $\frac{5}{4} - \frac{3}{4} \ C$ , E) (C, D) = ( $\frac{17}{7}, \ \frac{-4}{7}$

Explanation:

Part D) two expressions are indicated

3C + 4D = 5

2C +5 D = 2

let's simplify each expression

3C + 4D = 5

4D = 5 - 3C

we divide by 4

D = $\frac{5}{4} - \frac{3}{4} \ C$

The other expression

2C +5 D = 2

2C = 2 - 5D

C = $1 - \frac{5}{2} \ D$

we can see that the correct result is 1

Part E.

It is asked to solve the problem by the substitution method, we already have

D = $\frac{5}{4} - \frac{3}{4} \ C$

we substitute in the other equation

2C +5 D = 2

2C +5 (5/4 - ¾ C) = 2

we solve

C (2 - 15/4) + 25/4 = 2

-7 / 4 C = 2 - 25/4

-7 / 4 C = -17/4

7C = 17

C = $\frac{17}{7}$

now we calculate D

D = $\frac{5}{4} - \frac{3}{4} \ \frac{17}{7}$

D = 5/4 - 51/28

D = $\frac{35-51}{28}$

D = - 16/28

D = $- \frac{4}{7}$

the result is (C, D) = ( $\frac{17}{7}, \ \frac{-4}{7}$ )

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3 years ago

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Explanation:

Speed of the marathon runner, v = 9.51 mi/hr

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$v=\dfrac{d}{t}$

$t=\dfrac{d}{v}$

$t=\dfrac{26.220\ mi}{9.51\ mi/hr}$

t = 2.75 hours

Since, 1 hour = 60 minutes

t = 165 minutes

Since, 1 minute = 60 seconds

t = 9900 seconds

Hence, this is the required solution.

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Explanation:

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