Answer:
Explanation:
s = ut+ 0.5at²
u = 0
t = 6
a = 9.81
s = 0 + 0.5 * 9.81 * 36 = 176.58 m
v = u + at
v = 9.81* 36 = 353 m/s
Answer:a b c
Explanation: I’m not sure tho
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Answer:
B
Explanation:
From Newton's law of motion, we have:
V^2 = U^2 + 2gH
Where V and U are final and initial velocity respectively.
H is the height.
For the object to have a sustain a maximum height it means the final velocity of the object is zero.
By computing the height of the object sustain by A, we have:
0^2 = 2^2 -2×10×H
0= 4 -20H
4 = 20H;
H= 0.2m
For object B we have;
0^2 = 1^2 -2×10×H
0 = 1 -20H
H = 1/20= 0.05m
From computing the height sustain by both objects, we see object B is projected at a shorter height into atmosphere than A.
Hence object B will return to the ground first.
