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3 years ago

For which job would a noise canceling device be the most beneficial?

Physics

2 answers:

musickatia [10]3 years ago

8 0

A carpenter using saws and cutting tools as the tools make loud noises.

Alex Ar [27]3 years ago

6 0

Answer:

a carpenter using saws and cutting tools

Explanation:

In noise cancelling system we know that two sounds are cancelled just by using the concept of destructive interference.

Here when two sounds which are in opposite phase are superimposed with each other then due to this superposition of waves the resultant intensity will be less than the intensity of any individual wave.

This phenomenon is known as destructive interference.

This is used to decrease the level of sound in such a part of work where we have large sound in output so here correct answer will be

a carpenter using saws and cutting tools

This is because it produce large noise while we use this cutting tools

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If mr galans paces is equal to 1.8 m,how many paces would it take to get to the moon

Anettt [7]

Answer:

The number of paces it would take to get to the Moon is 213,555,556 paces

Explanation:

The given length of Mr Galan's paces = 1.8 m/pace

The distance from the Earth to the Moon is, 384,400 km = 384,400,000 m

Therefore, the number of paces, "n", it would take to get to the Moon from the Earth is given as follows;

n = (The distance from the Earth to the Moon)/(The length of each Mr Galan's paces)

∴ n = 384,400,000 m/(1.8 m/pace) = 213,555,556 paces

The number of paces it would take to get to the Moon = n = 213,555,556 paces

5 0

3 years ago

If the angle of reflection is 82 and the light ray strikes a flat mirror, what will the angle

il63 [147K]

Answer:

Explanation:

According to law of reflection, the angle of incidence = angle of reflection

4 0

3 years ago

Read 2 more answers

Block b rests upon a smooth surface. if the coefficients of static and kinetic friction between a and b are μs = 0.4 and μk = 0.

aliina [53]

Given

Weight of the block A, Wa = 20 lb, weight of block B Wb = 50 lb. Applied force to block A, P = 6lb, coefficient of static friction µs = 0.4, coefficient of kinetic friction µk = 0.3. If a force P is applied to the body, no relative motion will take place until the applied force is equal to the force of friction Ff, which is acting opposite to the direction of motion. Magnitude of static force of friction between block A and block B, Fs = µsN, where N is reaction force acting on block A. Now, resolve the forces Fx = max. P = (mA + mB)a,

6 = (20 / 32.2 + 50 / 32.2)a

2.173a = 6

A = 2.76 ft/s^2

To check slipping occurs between block A and block B, consider block A:

P – Ff = mAaA

6 – Ff = 1.71

Ff = 4.29 lb

And also,

N = wA. We know static friction,

Fs = µsN

Fs = 0.4 x 20

Fs = 8lb

Frictional force is less than static friction. Ff < Fs

<span>Therefors, acceleration of block A, aA = 2.76 ft/s^2, acceleration of block B aB = 2.76 ft/s^2</span>

6 0

3 years ago

A box has the dimensions of 50 cm × 30 cm × 15 cm, weighs 150 N, and is to be

nadezda [96]

The surface can only withstand a pressure Face A (50cm × 30cm) and Face C (50cm × 15cm) as the surface can only withstand a pressure of 0.25 N/cm³.

<h3>What is pressure?</h3>

The physical force used to apply pressure to an object is defined as such. Per square inch of an object, a force is applied perpendicularly to its surface. For pressure, the fundamental formula is F/A. (Force per unit area). The Pascal is the unit of pressure (Pa).

The four different types of pressure are absolute, atmospheric, differential, and gauge pressure. Have you ever noticed that when you use a straw to drink something, the air actually gets suked out? In reality, you're applying "Pressure" as you drink the beverage.

A box has the dimensions of 50 cm × 30 cm × 15 cm

Let each face be A, B and C

The weight of the box = 150 N

Formula for pressure is

P = F/A

To find out which face of the box can withstand a pressure of 0.25 N/cm

we need find the area of each face and find its pleasure

Face A = 50 cm × 30 cm

Area A = l × b

= 50 × 30

= 1500 cm²

Pressure A = 150/1500

= 0.1 N/cm³

0.25 > 0.1

The surface can definitively withstand the pressure of Face A

Face B = 30 cm × 15 cm

Area A = l × b

= 30 × 15

= 450 cm²

Pressure A = 150/450

= 0.3 N/cm³

0.25 < 0.3

The surface could not withstand the pressure of Face B

Face C = 50 cm × 15 cm

Area A = l × b

= 50 × 15

= 750 cm²

Pressure A = 150/750

= 0.2 N/cm³

0.25 > 0.2

The surface can definitively withstand the pressure of Face C

Thus, The surface can only withstand a pressure Face A (50cm × 30cm) and Face C (50cm × 15cm) as the surface can only withstand a pressure of 0.25 N/cm³.

Learn more about Pressure

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8 0

1 year ago

A student plucks a fixed-end string, creating a standing wave with 6.00 nodes (including any nodes at the ends). The string is t

Vesna [10]

1) 2.5 wavelengths

2) 0.208 m

3) 1731 Hz

Explanation:

Standing waves are waves that do not propagate, but instead the particles of the medium just oscillate around a fixed position. Examples of standing waves are the waves produced on a string with fixed ends.

The points of a standing wave in which the amplitude of the oscillation is always zero are called nodes.

The two fixed ends of the string are two nodes. In this problem, we have a total of 6 nodes along the string: this means that there are 4 additional nodes apart from the two ends of the string.

Therefore, this also means that the string oscillate in 5 different segments.

One wavelength is equal to 2 segments of the oscillation: therefore, since here there are 5 segments, this means that the number of wavelengths that we have in this string is

$n=\frac{5}{2}=2.5$

The wavelength of a wave is the distance between two consecutive crests (or throughs) of the wave.

The wavelength of a standing wave can be also measured as the distance between the nth-node and the (n+2)-th node: so, basically, the wavelength in a standing wave is twice the distance between two nodes:

$\lambda = 2 d$