<span>If "m" balls are thrown per second, the time taken for a ball to reach its maximum height will be 1/m seconds. How to get this? See that the next ball is thrown only when the previous ball reaches its maximum height. If 'm' balls were thrown in 1 second this means that each ball was attaining its maximum ht in 1/m seconds.
This was the main part. Now we can proceed to find maximum height in 2 ways-
a)
We know for upward journey ,
t=1/m
a=-g
v=u-gt
final velocity ,v = 0 (at highest point)
u
=gt = g/m
Now we can apply
h=ut-1/2 gt^2
Putting the values of u,t, we will get
h= g/2m^2
b)
The second method uses a trick that time taken to reach the maximum ht is same as time taken to fall down.
So, we will now consider the downward journey of ball which also takes 1/m seconds
We apply
h=ut+1/2gt^2
Here u=0 ,t=1/m
We will again get ,
h=g/2m^2</span>
Answer:
Electric Field = 3.369 x 10^4 N/C
Explanation:
Radius = r = (r1 + r2) / 2 = (1.6 + 3.6) /2 = 2.6 cm + 2.3 cm = 4.9 cm = 0.049 m
As we know, Electric field = E = kQ/r.r
= 8.98755 x 10^9 x 9 x 10^-9 / 0.049 x 0.049 = 33689.275 N/C
= 3.369 x 10^4 N/C
18 electrons because protons minus the atomic mass so it would be 35-17 which gives you 18.
Answer:
The correct option is;
Raymond: I think the skateboarder has the same total energy at all points on the ramp
Explanation:
The total energy, also known as the total mechanical energy, is the sum of the kinetic and potential energies of the skateboarder
Given that the potential energy is the energy gained due to elevation, the maximum potential energy is obtained at the top of the ramp, while the maximum kinetic energy, which is the energy due to motion, is at the bottom of the ramp where the skateboarder moves fastest.
However, by the energy conservation principle, the kinetic energy of he skateboarder comes from the conversion of the potential energy, such that the total energy is the same at any particular point on the ramp.
