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Oduvanchick [21]
3 years ago
15

A 1 mL pipette delivers a measured volume of .98 mL (calculate the percentage error)

Chemistry
2 answers:
Natalija [7]3 years ago
4 0

Answer:

2%

Explanation:

.98 is 98% of one and therefore they are missing 2%

r-ruslan [8.4K]3 years ago
4 0

Answer:

2%

Explanation:

The answer is 2%.

100-98 is 2.

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4Na (s) + O2 (g) - 2Na20 (s)
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How much excess reagent remains when the reaction is over? ... 3) How many grams of sodium nitrate will be produced from 4.3 mol lead(ID.

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liquid octane(CH3)(CH2)6CH3) reacts with gaseous oxygen gas(O2) to produce gaseous carbon dioxide(CO2) and gaseous water(H2O). I
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The percent yield of carbon dioxide will be 49.0 %.

<h3>Percent yield</h3>

First, let's look at the equation of the reaction:

2C_8H_1_8 + 25O_2 -- > 16CO_2 + 18H_2O

The mole ratio of octane to oxygen is 2:25.

Mole of 3.43 g octane = 3.43/114.23 = 0.03 mol

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More on percent yield can be found here: brainly.com/question/17042787

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6 0
1 year ago
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There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. Cac
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Answer:

The equation that gives the overall equilibrium in terms of the equilibrium constants K and Ky is K1 = K^6 * Ky

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we have the following balanced reaction:

CaC2 + 2H2O = C2H2 + Ca(OH)2

the value of K for this reaction will be equal to:

K = ([C2H2] * [Ca(OH)2])/([CaC2] * [H2O]^2)

if we multiply the reaction by the value of 6, we have:

6CaC2 + 12H2O = 6C2H2 + 6Ca(OH)2

Again, the value of K for this reaction will be equal to:

K,´ = ([C2H2] ^6 * [Ca(OH)2]^6)/([CaC2]^6 * [H2O]^12) = K^6

For the second reaction:

6C2H2 + 3CO2 + 4H2O = 5CH2CHCO2H

The value of K for this reaction:

K2 = ([CH2CHCO2H]^5)/([C2H2]^6 * [CO2]^3 * [H2O]^4)

we also have:

K1 = ([CH2CHCO2H]^5)/([C2H2]^6 * [CO2]^3 * [H2O]^16)

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K1 = K^6 * Ky

4 0
3 years ago
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