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VARVARA [1.3K]
3 years ago
6

A bumblebee flies with a ground speed of 15.0 m/s . Calculate its speed in km/h.

Chemistry
2 answers:
e-lub [12.9K]3 years ago
8 0

Answer:

54\frac{km}{h}

Explanation:

This is a problem of conversion of units.

First of all you need to take the quantity the problem gives you and write it down with the units:

15.0\frac{m}{s}

Then you need to find the conversion factor for the units you need to convert:

In this case you need to convert from meters (m) to kilometers (km) and from seconds (s) to hours (h), so you have the following conversion factors:

- To convert from meters (m) to kilometers (km):

15.0\frac{m}{s}*\frac{1km}{1000m}

-To convert from seconds (s) to hours (h):

15.0\frac{m}{s}*\frac{3600s}{1h}

Then you should put the conversion factors in the same expression, so:

15.0\frac{m}{s}*\frac{1km}{1000m}*\frac{3600s}{1h}

Finally you multiply the numerators and the denominators and divide the results:

15.0\frac{m}{s}*\frac{1km}{1000m}*\frac{3600s}{1h}=54\frac{km}{h}

zheka24 [161]3 years ago
5 0
Speed in km/hr = 15 x 18
                            ------------
                                 5
             
                          =   54 km/hr.

Hope this helps!

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Answer:

Part A:

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Part B:

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Explanation:

Monatomic ions:

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Part A:

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Phosphorous (P) has 15 electrons so it require 3 more electrons to stabilize itself.

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Part B:

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Magnesium (Mg) has 12 electrons so it requires 2 electrons to lose to achieve stable configuration.

Charge is Mg^{2+}

Full ground-state electron configuration of the mono atomic ion:

1s^2 2s^22p^6

Part C:

For Se:

Selenium (Se) has 34 electrons and requires two electrons to be stable.

Charge is Se^{2-}

Full ground-state electron configuration of the mono atomic ion:

1s^2 2s^22p^63s^23p^64s^23d^{10}4p^6

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Answer:

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