How should the following reaction be classified?

Chemistry

1 answer:

Tanya [424]2 years ago

6 0

B.) Decomposition
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10. Which best explains why the total mass of the product(s) would be less than the total weight of the

Olegator [25]

Answer:

D. Gases were released to the atmosphere

Explanation:

In accordance to the law of conservation of mass, the total amount of reactants must equate the total amount of products at the end of the reaction because matter can not be lost or created. However, certain changes like gas evolution, formation of precipitate etc. indicates the occurrence of a chemical reaction.

In a chemical reaction, the total mass of the product(s) would be less than the total weight of the reactant(s) because GASES, which constituted part of the mass of the reaction, WERE RELEASED INTO THE ATMOSPHERE. However, if the mass of the gas released can be accounted for, the amount of reactants and products must balance.

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Change 32L of carbon dioxide into moles of carbon dioxide

kaheart [24]

32L —> 32000g —> 727.116 Moles (rounded)

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Which causes genetic variations and can result in different alleles? O predation rate O random mutations O competition o environ

alekssr [168]

Answer:

Explanation:

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2.17 in to 10^23 molecules of Br 2 to moles

KiRa [710]

I don't get what you are saying... Can you reword it?

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2 years ago

A galvanic cell consists of a Cu(s)|Cu2+(aq) half-cell and a Cd(s)|Cd2+(aq) half-cell connected by a salt bridge. Oxidation occu

Kryger [21]

Answer:

$Cd(s)|Cd^{2+}(aq) || Cu^{2+}(aq)|Cu(s)$

Explanation:

A galvanic cell is composed of two electrodes immersed in a suitable electrolyte and connected via a salt bridge. One of the electrodes serves as a cathode where reduction or gain of electrons takes place. The other half cell functions as an anode where oxidation or loss of electrons occurs.

The representation is given by writing the anode on left hand side followed by its ion with its molar concentration. It is followed by a salt bridge. Then the cathodic ion with its molar concentration is written and then the cathode.

As it is given that cadmium acts as anode, it must be on the left hand side and copper must be on right hand side.

$Cd(s)|Cd^{2+}(aq) || Cu^{2+}(aq)|Cu(s)$

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3 years ago