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Anna35 [415]
3 years ago
15

Could you please help

Chemistry
1 answer:
Semenov [28]3 years ago
8 0
I would say D, because you need to start with nothing to measure the different sizes as they start to grow. hope this helps!
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Explanation:

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             \frac{1 g}{1000 mg} or \frac{1000 mg}{1 g}

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If the detector is capturing 3.3×108 photons per second at this wavelength, what is the total energy of the photons detected in
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Answer:

The total energy of the photons detected in one hour is 7.04*10⁻¹¹ J

Explanation:

The energy carried by electromagnetic radiation is displaced by waves. This energy is not continuous, but is transmitted grouped into small "quanta" of energy called photons. The energy (E) carried by electromagnetic radiation can be measured in Joules (J). Frequency (ν or f) is the number of times a wave oscillates in one second and is measured in cycles / second or hertz (Hz). The frequency is directly proportional to the energy carried by a radiation, according to the equation: E = h.f, (where h is the Planck constant = 6.63 · 10⁻³⁴ J / s).

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E=\frac{h*speed of light}{wavelength}

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E=\frac{6.63*10^{-34}*3*10^{8}}{3.35*10^{-3} }

E=5.93*10⁻²³ \frac{J}{proton}

The detector is capturing  3.3*10⁸ photons per second. So, in 1 hour:

E=5.93*10^{-23} \frac{J}{proton} *3.3*10^{8} \frac{proton}{s} *\frac{60}{1} \frac{s}{minute} *\frac{60}{1} \frac{minute}{hr}

E=7.04*10⁻¹¹ \frac{J}{hr}

The total energy of the photons detected in one hour is 7.04*10⁻¹¹ J

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