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11 months ago

Which chemical formula corresponds to this structural formula? c6h6h6h2 c14h6 c6h12 c6h14

Chemistry

2 answers:

Alexxandr [17]11 months ago

6 0

The chemical formula C₂H₆O, which is designated as option D, is equivalent to this structural formula.

<h3><u>What is a Chemical Formula ?</u></h3>

Chemical element symbols, numbers, and occasionally additional symbols like parentheses, dashes, brackets, commas, and plus (+) and minus () signs are used in a chemical formula to represent information about the chemical proportions of the atoms that make up a certain chemical compound or molecule.

An empirical formula represents by symbols, such as Na for sodium and Cl for chlorine, with subscripts that show the relative number of atoms in each.
The composition of any member of an entire class of compounds can be represented by a general formula, a sort of empirical formula.

To know more about Chemical formulas, refer to:

brainly.com/question/26388921

Yuri [45]11 months ago

4 0

Answer:

its d

Explanation:

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Data collected that describes the quality of the data set is called _______ data.

Nitella [24]

Answer:

1. Qualitative.

2. Comparative investigation.

3. Mode.

Explanation:

1. Data collected that describes the quality of the data set is called qualitative data. This data type are non-numerical in nature i.e they are categorical. Some examples are excellent, poor, gender, religion etc.

2. An investigation where you compare objects to find a relationship is a comparative investigation. For example, a researcher trying to find out which bag is heavier by determining their weight.

3. If the number 5 occurs with the most frequency in the data set, it is called the mode.

For example, given A = (1, 5, 2, 5, 1, 5 4, 5). The mode is 5 because it appeared the most i.e four (4) times.

3 0

3 years ago

Fe(s) + CuSO4(aq) <===> Cu(s) + FeSO4(aq)

Ludmilka [50]

Answer : The original concentration of copper (II) sulfate in the sample is, $5.6\times 10^{-1}g/L$

Explanation :

Molar mass of Cu = 63.5 g/mol

First we have to calculate the number of moles of Cu.

Number of moles of Cu = $\frac{\text{Mass of Cu}}{\text{Molar mass of Cu}}=\frac{89\times 10^{-3}g}{63.5g/mol}=1.40\times 10^{-3}mole$

Now we have to calculate the number of moles of $CuSO_4$

Number of moles of Cu = Number of moles of $CuSO_4$

Number of moles of $CuSO_4$ = $1.40\times 10^{-3}mole$

Now we have to calculate the molarity of $CuSO_4$

$\text{Molarity}=\frac{\text{Moles of }CuSO_4\times 1000}{\text{Volume of solution (in mL)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{1.40\times 10^{-3}mole\times 1000}{400.mL}=0.0035M$

To change mol/L into g/L, we need to multiply it with molar mass of $CuSO_4$

Molar mass of $CuSO_4$ = 159.609 g/mL

Concentration in g/L = $0.0035M\times 159.609g/mol=0.5586g/L\approx 5.6\times 10^{-1}g/L$

Thus, the original concentration of copper (II) sulfate in the sample is, $5.6\times 10^{-1}g/L$

3 0

3 years ago

Convert the following to number of moles: 4.03 x 10^21 molecules present in AgNO3

castortr0y [4]

Moles = 4.03 x 10^21
------------------------
6.02 x 10^23

= 6.69 x 10^-3 moles.
Hope this helps!

6 0

3 years ago

A 250 cm^3 solution containing 1,46 g of sodium chloride is added to an excess of silver nitrate solution. The reaction is given

faust18 [17]

Answer:

The mass of the precipitate that AgCl is 3.5803 g.

Explanation:

a) To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Mass of solute (NaCl) = 1.46 g

Molar mass of sulfuric acid = 58.5 g/mol

Volume of solution = $250 cm^3 =250 mL$

$1 cm^3= 1 ml$

Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{1.46g\times 1000}{58.5g/mol\times 250}\\\\\text{Molarity of solution}=0.09982 M$

0.09982 M is the concentration of the sodium chloride solution.

b) $NaCl (aq)+AgNO_3 (aq)\rightarrow AgCI(s)+NaNO_3(aq)$

Moles of NaCl = $\frac{1.46 g}{58.5 g/mol}=0.02495 mol$

according to reaction 1 mol of NaCl gives 1 mol of AgCl.

Then 0.02495 moles of NaCl will give:

$\frac{1}{1}\times 0.02495 mol=0.02495 mol$ of AgCl

Mass of 0.02495 moles of AgCl:

$0.02495 mol\times 143.5 g/mol=3.5803 g$

The mass of the precipitate that AgCl is 3.5803 g.

3 0

3 years ago

Specific amino acids that line the selectivity filter of the K channel can dehydrate K and allow passage of that ion but cannot

Bogdan [553]

Answer:

True

Explanation:

Since on the inner and outer surfaces of the membrane, a series of negatively charged amino acids are found, which increase the local concentration of cations. The path of the ions begins on the inner surface filled with water molecules where the ion can retain its hydration sphere. Two thirds of its interior in the membrane the inside of the channel narrows in the region of the selectivity filter, forcing the ion to separate from the water molecules. Oxygen atoms in the selectivity filter replace the water molecules in the K+ hydration sphere, forming a series of coordination spheres through which the ion moves. The preferential stabilization of K+ against Na+ is the basis of the ion selectivity of this filter.

5 0

3 years ago