Ask question

Ask question

All categories

4 years ago

7

What is density?

1 answer:

AleksAgata [21]4 years ago

5 0

Answer:

<em>B. A measure of mass per unit volume </em>

Explanation:

You might be interested in

Someone please help me!

beks73 [17]

Answer:

current = 8,750

Explanation:

you will need to use the formula i = v/r to get this answer

3 0

3 years ago

castortr0y [4]

Answer: $Q=3000 cal$

Explanation:

We are given the following formula:

$Q=m. c. \Delta T$ (1)

Where:

$Q=3000 cal$ is the amount of heat

$m=300g$ is the mass of water

$c=1 cal/g \°C$ is the specific heat of water

$\Delta T$ is the variation in temperature, which in this case is $\Delta T=30\°C-20\°C=10\°C$

Rewriting equation (1) with the known values at the right side, we will prove the result is $3000 cal$ :

$Q=(300g)(1 cal/g \°C)(10\°C)$ (2)

$Q=3000 cal$ This is the result

8 0

3 years ago

In an NMR experiment, the RF source oscillates at 34 MHz and magnetic resonance of the hydrogen atoms in the sample being in- ve

choli [55]

Answer:

$B_{int}=-0.015T$

Explanation:

From the question we are told that:

RF source oscillation speed $\sigma= 34 MHz$

The external field $Bext =0.78 T$ .

Pro- ton magnetic moment component $\mu=1.41 X 10-26 J/T$

Generally the equation for magnitude of $B_{int}$ is mathematically given by

$B_{int}=B_{ext}-\frac{h\triangle \sigma}{2 \mu}$

$B_{int}=0.78-\frac{6.6*10^{-34}*34*10^6}{2*1.41*10^{26}}$

$B_{int}=0.78-0.7957$

$B_{int}=-0.015T$

6 0

3 years ago

Will an object with a density of 1.05 g/ml float or sink in water? Explain.

WINSTONCH [101]

It will sink because it is heavier. The density of water 1.00 g/ml

7 0

3 years ago

A defibrillator containing a 18.4 μF capacitor is used to shock the heart of a patient by holding it to the patient's chest. Jus

gregori [183]

Answer:

The energy E is 1603.008 J.

Explanation:

Given that,

Capacitor = 18.4 μF

Voltage = 13.2 kV

We need to calculate the energy

Using formula of energy

$E=W=\int{Q}\ dV$ .....(I)

We know that,

$Q=CV$

Put the value of Q in equation (I)

$E=\int{CV}dV$

On integration

$E=\dfrac{CV^2}{2}$

Put the value into the formula

$E=\dfrac{18.4\times10^{-6}\times(13.2\times10^{3})^2}{2}$

$E=1603.008\ J$

Hence, The energy E is 1603.008 J.

3 0

3 years ago