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SSSSS [86.1K]
3 years ago
14

At what forward voltage does a diode conduct a current equal to 10,000 Is ? In terms of Is , what current flows in the same diod

e when its forward voltage is 0.7 V?
Engineering
1 answer:
zhenek [66]3 years ago
6 0

Answer:

a) The forward voltage is 0.23 V

b) The current that flows  I_{d} =  (1.45*10^{12}I_{s})A

Explanation:

The forward voltage is the minimum voltage that must be applied to a diode before it starts to conduct. The equation is given by:

a) At what forward voltage does a diode conduct a current equal to 10,000 Is ? In terms of Is

I_{d} =  I_{s}(e^{\frac{v_{f} }{0.025} }-1)

Where:

Id is the diode current = 10000Is,

Vd is the forward voltage at which the diode begins to conduct,

Is is the saturation current.

I_{d} =  I_{s}(e^{\frac{v_{f} }{0.025} }-1)

10000I_{s} =  I_{s}(e^{\frac{v_{f} }{0.025} }-1)

Dividing through by Is,

10000 =  (e^{\frac{v_{f} }{0.025} }-1)

10000 +1=  e^{\frac{v_{f} }{0.025} }

10001=  e^{\frac{v_{f} }{0.025} }

Taking the natural logarithm of both sides,

ln(10001)=  {\frac{v_{f} }{0.025} }

9.21=  {\frac{v_{f} }{0.025} }

multiplying through by 0.025

{v_{f} }= 0.23 = 0.23 V

The forward voltage does a diode conduct a current equal to 10,000 Is is 0.23 V

b) what current flows in the same diode when its forward voltage is 0.7 V?

I_{d} =  I_{s}(e^{\frac{v_{f} }{0.025} }-1)

I_{d} =  I_{s}(e^{\frac{0.7}{0.025} }-1)

I_{d} =  I_{s}(1.45*10^{12} -1)

I_{d} =  (1.45*10^{12}I_{s})A

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Air flows steadily and isentropically from standard atmospheric conditions to a receiver pipe through a converging duct. The cro
Liula [17]

Answer:

The answer is "0.0728"

Explanation:

Given value:

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                                     = 14.696\times (\frac{2}{1.4+1})^{\frac{1.4}{1.4-1}}\\\\=7.763 Psia\\\\

if P flow is chocked

if P>P^{*} \to flow is not chocked

When  P= 10 psia < P^{*} \to not chocked

match number:

\ for \ P= \ 10\ G= \sqrt{\frac{2}{k-1}[(\frac{\ p_{0}}{p})^{\frac{k-1}{k}}-1]}

                       = \sqrt{\frac{2}{1.4-1}[(\frac{14.696}{10})^{\frac{1.4-1}{1.4}}-1]}

M_0=7.625

p=p_0(1+\frac{k-1}{2} M_0 r)^\frac{1}{1-k}

  =0.00238(1+\frac{1.4-1}{2}0.7625`)^{\frac{1}{1-1.4}}\\\\\ p=0.001808 \frac{slug}{ft^3}

\ T= T_0(1+\frac{k-1}{2} Ma^r)^{-1}\\\\\ T=518.67(1+\frac{1.4-1}{2} 0.7625^2)^{-1}\\\\\ T=464.6R\\\\

\ velocity \ of \ sound \ (C)=\sqrt{KRT}\\\\

                                    =\sqrt{1.4\times1716\times464.6}\\\\=1057 ft^3\\\\

R= gas constant=1716

m=PAV\\\\

    =0.001808\times0.05\times(Ma.C)\\\\=0.001808\times0.05\times0.7625\times 1057\\\\=0.0728\frac{slug}{s}

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Calculate the density of a hydraulic oil in units of kg/m^3 knowing that the density is 1.74 slugs/ft^3. Then, calculate the spe
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Answer:

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We have given density of oil is 1.74 slugs/ft^3

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We know that 1 slugs = 14.5939 kg

So 1.74 slug = 1.74×14.5939 = 25.3933 kg

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Listed below are snippets from a prgram to perform input validation for
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Answer:

#include <iostream>

#include <string>

#include "user.h"

#include "password.h"

using namespace Authenticate;

using namespace std;

int main()

{

inputUserName();

inputPassword();

cout << "Your username is " << getUserName() <<

" and your password is: " <<

getPassword() << endl;

return 0;

}

user.h:

#ifndef USER_H

#define USER_H

#include <string>

using namespace std;

namespace Authenticate

{

namespace

{

bool isvalid();

}

void inputUserName();

string getUserName();

}

#endif

user.cpp:

#include <iostream>

#include "user.h"

namespace Authenticate

{

string username="";

namespace

{

bool isvalid()

{

if(username.length() == 8)

return true;

else

return false;

}

}

void inputUserName(){

do

{

cout << "Enter your username (8 letters only)" << endl;

cin >> username;

}

while(!isvalid());

}

string getUserName()

{

return username;

}

}

password.h:

#ifndef PASSWORD_h

#define PASSWORD_h

#include <string>

using namespace std;

namespace Authenticate

{

namespace

{

bool isValid();

}

void inputPassword();

string getPassword();

}

#endif

password.cpp:

#include <iostream>

#include <string>

using namespace std;

namespace Authenticate

{

string password="";

namespace

{

bool isValid()

{

if(password.length() >= 8)

{

for(int i=0; i<password.length(); i++)

if(password[i] >= '0' && password[i] <= '9')

return true;

return false;

}

else

return false;

}

}

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do

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"and at leat one non-letter)" << endl;

cin >> password;

}

while(!isValid());

}

string getPassword()

{

return password;

}

}

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