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kobusy [5.1K]
10 months ago
7

A common boundary-crossing problem for engineers is when their home country' values come into sharp contrast with the host count

rys" values O True o fare 10 pts Question 10 Which of the following are common ethical problems that engineers might encounter when working abroad, particularly among cultures that are considered vulnerable populations? Select that oly Uncomenda
Engineering
1 answer:
nikdorinn [45]10 months ago
8 0

A dual relationship that is acceptable, maybe inevitable, or impossible to avoid is often classified as a boundary crossing.

<h3>What is Boundary Crossing?</h3>
  • A dual relationship that is acceptable, maybe inevitable, or impossible to avoid is often classified as a boundary crossing.
  • For instance, if you reside in a small town or rural area, it is likely that you will cross boundaries and interact with clients who are not in a professional setting. It's just a reality of life; it's not necessarily unethical, and managing those boundary problems well is necessary.
  • Another illustration is when your spouse or partner collaborates with your customer. A boundary has been crossed. You might attend a holiday party that your spouse's or partner's company sponsored since you were invited, only to find out afterwards that your client is there because they both work for the same company or have done business together.

To Learn more About  boundary crossing refer to:

brainly.com/question/8344761

#SPJ4

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Generally, final design results are rounded to or fixed to three digits because the given data cannot justify a greater display.
creativ13 [48]

Answer:

(a) 1.90 kpsi

(b) 0.40 kpsi

(c) 0.61 in.

(d) 0.009

(a) 8 MPa

(b) 1.30 cm⁴

(c) 2.04 cm⁴

(d) 62.2 MPa

Explanation:

(a) σ = M/Z, where M = 1770 lbf·in and Z = 0.943 in³.

1770/0.943 = 1876.988 lbf/in² = 1.90 kpsi

(b) σ = F/A, where F = 9440 lbf and A = 23.8 in².

9440 /23.8 = 396.639 lbf/in² = 0.4 kpsi

(c) y = Fl³/(3EI)

F = 270 lbf

l = 31.5 in.

E = 30 Mpsi

I = 0.154 in.⁴

y = 270×31.5³/(3×30×10⁶×0.154) = 0.61 in.

(d) θ = Tl/(GJ), where T = 9740 lbf·in, l = 9.85 in. G = 11.3 Mpsi, and d = 1.00 in.

J = π·d⁴/32 = π/32 in.⁴

∴ θ = 9740  × 9.85 /(11.3 × 10⁶× π/32) = 0.009

(a) σ = F/wt, where F = 1 kN, w = 25 mm, and t = 5 mm

∴ σ = 1000/(0.025 × 0.005) = 8 MPa

(b) I = bh³/12, where b = 10 mm and h = 25 mm.

10×25³/12 = 1.30 cm⁴

(c) I = π·d⁴/64 where d = 25.4 mm.

I = π × 25.4⁴/64 = 2.04 cm⁴

(d) τ = 16×T/(π×d³), where T = 25 N·m, and d = 12.7 mm.

16×25/(π×0.0127³) = 62.2 MPa.

8 0
3 years ago
Q1. (20 marks) Entropy Analysis of the heat engine: consider a 35% efficient heat engine operating between a large, high- temper
Anvisha [2.4K]

The rate of gain for the high reservoir would be 780 kj/s.

A. η = 35%

\frac{w}{Q1} = \frac{35}{100}

W = 1.2*\frac{35}{100}*1000kj/s

W = 420 kj/s

Q2 = Q1-W

= 1200-420

= 780 kJ/S

<h3>What is the workdone by this engine?</h3>

B. W = 420 kj/s

= 420x1000 w

= 4.2x10⁵W

The work done is 4.2x10⁵W

c. 780/308 - 1200/1000

= 2.532 - 1.2

= 1.332kj

The total enthropy gain is 1.332kj

D. Q1 = 1200

T1 = 1000

\frac{1200}{1000} =\frac{Q2}{308} \\\\Q2 = 369.6 KJ

<h3>Cournot efficiency = W/Q1</h3>

= 1200 - 369.6/1200

= 69.2 percent

change in s is zero for the reversible heat engine.

Read more on enthropy here: brainly.com/question/6364271

6 0
2 years ago
Can anyone explain how a Halbek Device works
dedylja [7]

Answer:

The Halbek Device can be used effectively on some weapons with practice and certain loadouts. ... This tends to help high-damage weapons or weapons with high multipliers

8 0
2 years ago
Read 2 more answers
Suppose a large amount of power is required. Which engine would you choose between Otto and Diesel? Why?
Firdavs [7]

Answer:

Otto engine

Explanation:

As we know that

Power = Torque x speed

So we can say that when speed of engine then power of engine also will increases.

The speed of Otto engine is more as compare to Diesel engine so the power of Otto engine is more.But on the other hand torque of Diesel engine is more as compare to Otto engine but the speed is low so the product of speed and torque is more for Otto engine .It means that when requires large amount of power then Otto engine should be use.

6 0
3 years ago
Select the correct answer.
Elodia [21]
I think balance




Can I get Brainlyist
3 0
3 years ago
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