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svetoff [14.1K]
3 years ago
9

A baseball is thrown with a vertical velocity of 50 ft/s from an initial height of 6 ft. The height h in feet of the baseball ca

n be modeled by h(t) = -16t2 + 50t + 6, where t is the time in seconds since the ball was thrown. It takes the ball approximately
seconds to reach its maximum height. (Round to the nearest tenth of a second and enter only the number.)

To the nearest foot, what is the maximum height that the ball reaches? (Enter only the number.)

A player hits a foul ball with an initial vertical velocity of 70 ft/s and an initial height of 5 feet. The maximum height reached by the ball is
feet. (Round to the nearest foot and enter only the number.)

I need the answers.
Mathematics
1 answer:
Bad White [126]3 years ago
4 0
Vertex is highest point


ok so the t value of the vertex of a function in the form
f(x)=at^2+bt+c is
-b/2a

find t value
h(x)=-16t^2+50t+6
a=-16
b=50
-50/(2*-16)=1.5625
round
1.6 seconds
max height
input 1.6 for t and evaluate (for more precice, input 1.5625 for t)

max height is 45 feet



seems to be
b=initial velocity
c=intial height

a=-16
eqation is
h(t)=-16t^2+70t+5
vertex is -70/(2*-16)=2.1875
input for t to get max height
82 feet



answers are

1.6 seconds
45 feet
82 feet
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7/12.

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3 years ago
9. Nadeem plans to ride her bike between
Paul [167]

Answer:

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d = vt

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2 years ago
The transitive property holds true for similar figures.<br><br> Always<br> Sometimes<br> Never
liubo4ka [24]

Answer: Always.


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5 0
3 years ago
Read 2 more answers
A telemarketer is successful at getting people to donate money for her organization in 55% of all calls she makes. She must get
Tems11 [23]
An interesting twist to a binomial distribution problem.

Given:
p=55%=0.55 for probability of success in solicitation
x=4=number of successful solicitations
n=number of calls to be made
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From context of question, all calls are assumed independent, with constant probability of success, so binomial distribution is applicable.

The number of successes, x, is then given by
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x=number of successesC(n,x)=\frac{n!}{x!(n-x)!}

Here we need n such that
P(x,n,p)>=0.899
given
x>=4, p=0.55, which means we need to find

Method 1: if a cumulative binomial distribution table is available, we can look up n=9,10,11 and find
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So she must make (at least) 11 calls to make sure the probability of meeting her quota is 89.9% or more.

Method 2: using technology.
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Method 3: using simple calculator
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P(0,10,0.55)=0.000341
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P(3,10,0.55)=0.074603
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S=0.000341+0.004162+0.022890+0.074603
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8 0
3 years ago
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Sergio [31]

Answer:

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Step-by-step explanation:

Given that:

Cosec (t) = -\frac{13}5

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That means, angle t is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

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In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

cosec^2\theta -cot^2\theta =1

here, \theta =t

So, cosec^2t-cot^2t=1

\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}

But, angle t is in 3rd quadrant, so value of

\bold{cot(t) =\dfrac{12}{5}}

4 0
3 years ago
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