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antiseptic1488 [7]
3 years ago
7

Assuming ideal gas behavior, what is the pressure in atm exerted by 1.57 mol Cl2(g) confined to a volume of 1.50 L at 273K?

Chemistry
1 answer:
klio [65]3 years ago
5 0

The formula for ideal gas law is:

P V = n R T

where

P is pressure = ?

V is volume = 1.50 L

n is number of moles = 1.57 mol

R is gas constant = 0.08205746 L atm / mol K

T is temperature = 273 K

 

P = 1.57 mol * 0.08205746 L atm / mol K * 273 K / 1.50 L

<span>P = 23.45 atm</span>

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How are Newton's three laws of motion related
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3 years ago
Read 2 more answers
when 2.4 g zinc is added to hydrochloric acid, 450 ml of hydrogen gas form at a temperature of 32 C what is the pressure of the
Dovator [93]
First we need to find the number of moles of hydrogen gas formed
Zn + 2HCl ---> ZnCl₂ + H₂
stoichiometry of Zn to H₂ is 1:1
the number of Zn moles reacted - 2.4 g / 65.4 g/mol = 0.0367 mol
assuming Zn to be the limiting reactant 
number of Zn moles reacted = number of H₂ moles formed 
therefore number of H₂ moles formed = 0.0367 mol

we can use ideal gas law equation to find the pressure
PV = nRT
P - pressure
V - Volume - 450 x 10⁻⁶ m³
n - number of moles - 0.0367 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 32 °C + 273 = 305 K
substituting these values in the equation 
P x 450 x 10⁻⁶ m³ = 0.0367 mol x 8.314 Jmol⁻¹K⁻¹ x 305 K
P = 206.8 kPa 
pressure is 206.8 kPa
6 0
3 years ago
What is the value of for this aqueous reaction at 298 K? <br> A+B↽⇀C+D<br> ΔG°=12.86 kJ/mol<br> K=
kogti [31]

Answer:

Kc = 0.5951 (4 sig. figs.)

Explanation:

For A + B ⇄ C + D at standard thermodynamic conditions (298K, 1atm)

ΔG = ΔG° + R·T·lnQ => 0 = ΔG° + R·T·lnKc => ΔG° = - R·T·lnKc

=> lnKc = - ΔG°/R·T

ΔG° = +12.86 Kj/mol

R = 8.314 Kj/mol·K

T = 298K

lnKc = - (+12.86Kj) / (8.314Kj/mol·K)(298K) = - 0.519 mol⁻¹

Kc = e⁻⁰°⁵¹⁹ mol⁻¹ = 0.5957 mol⁻¹ (4 sig. figs.)

5 0
3 years ago
A vacuum gage connected to a chamber reads 35 kpa at a location where the atmospheric pressure is 92 kpa. determine the absolute
stealth61 [152]

Vacuum gage connected to a chamber reads 35 kpa at a location where the atmospheric pressure is 92 kpa then the  absolute pressure in the chamber and express is 57kpa

Gauge pressure is the pressure relative to atmospheric pressure. Gauge pressure is positive for pressures above atmospheric pressure, and negative for pressures and absolute pressure is the sum of gauge pressure and atmospheric pressure

Here to find absolute pressure atmospheric pressure=92kpa and  vacuum gage=35 kpa                                      

Pabsolute pressure=Patmospehric pressure - Pvaccume

92-35=57kpa

Know more about absolute pressure

brainly.com/question/28498660

#SPJ4

6 0
1 year ago
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