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AlexFokin [52]
2 years ago
9

What will Number 17 be?

Chemistry
1 answer:
katovenus [111]2 years ago
4 0
The unbalanced Equation is
electricity
KI (aq) + H2O (l) -------------> H2 (g) + I2(g) + KOH(aq)
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If 14.5 g of MnO4- (permanganate) react with manganese (II) hydroxide how many grams of manganese (IV) oxide will be produced? T
Veronika [31]

Answer:

m_{MnO_2}=21.2gMnO_2

Explanation:

Hello,

In this case, given the balanced reaction:

2MnO_4^-+2Mn(OH)_2\rightarrow 4MnO_2+2OH^-+H_2O

We can see a 2:4 mole ration between permanganate ion (118.9 g/mol) and manganese (IV) oxide (86.9 g/mol), that is why the resulting mas of this last one turns out:

m_{MnO_2}=14.5gMnO_4^-*\frac{1molMnO_4^-}{118.9gMnO_4^-}*\frac{4MnO_2}{2molMnO_4^-}  *\frac{86.9gMnO_2}{1molMnO_2} \\\\m_{MnO_2}=21.2gMnO_2

Best regards.

5 0
3 years ago
Joanna is performing a reaction that generates a moderate amount of hydroxide. To mimic biological conditions (most bodily fluid
Nady [450]

Answer:

As for your question, I know to forget to put the options, specifically that your question is incomplete.

Explanation:

Although it could help you by telling you that always a reaction that seeks to balance the pH, and achieve neutrality ... It is necessary to achieve a concentration of OH equal to that of H +, in this way the hydroxyl and the protons.

7 0
3 years ago
PLEASE HELP!!!
Inga [223]

Answer:

d=1.5\ g/cm^3

Explanation:

Given that,

The mass of the rock, m = 15 g

The volume of the rock, V = 10 cm³

We need to find the density of the rock. The density of an object is equal to the mass per unit volume such that,

d=\dfrac{m}{V}\\\\d=\dfrac{15\ g}{10\ cm^3}\\\\d=1.5\ g/cm^3

So, the density of the rock is equal to 1.5\ g/cm^3.

3 0
3 years ago
What is the name and formula of Calcium & Antimony
Bess [88]

Answer:

<h3>Ca3Sb2</h3>
  • Antimony--calcium (2/3) | Ca3Sb2 - PubChem.

Explanation:

I hope it's help

7 0
3 years ago
If you heat your melting point tube too quickly, what will your observed melting point be in comparison to the actual melting po
solniwko [45]

Explanation:

When conducting a melting point experiment, if we were to heat a sample quickly. Large amount heat is provided instantly which would melt the crystals in the tube very quickly, even before the temperature of the thermometer reaches to that level. So the observes melting point would be much lower than the actual melting point when sample is heated slowly.

5 0
3 years ago
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