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AlexFokin [52]
3 years ago
9

What will Number 17 be?

Chemistry
1 answer:
katovenus [111]3 years ago
4 0
The unbalanced Equation is
electricity
KI (aq) + H2O (l) -------------> H2 (g) + I2(g) + KOH(aq)
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Among the alkali earth metals, the tendency to react with other substances
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What is callibration of temperature
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3 0
3 years ago
The partial pressure of CH4 is 0.175 atm and that of O2 is 0.250 atm in a mixture of the two gases. What is the mole fraction of
tresset_1 [31]

Answer:

The total number of moles of gas in the mixture is 0.16939.

1.25550 grams of methane gas and 3.18848 grams of oxygen gas.

Explanation:

Total volume of the mixture = V = 10.5 L

Temperature of the mixture = T = 35°C = 308.15K

Pressure of the mixture = P

Total moles of mixture = n =n_1+n_2

Using an ideal gas equation :

PV=nRT

P\times 10.0 L=n\times 0.0821 atm L/mol K\times 308.15 K

P=2.509 n

Partial pressure of the methane= p_1=0.175 atm

Moles of the methane= n_1

Partial pressure of the oxygen gas= p_2=0.250 atm

Moles of the methane= n_2

Mole fraction  of the methane= \chi_1=\frac{n_1}{n_1+n_2}

Mole fraction  of the oxygen gas= \chi_2=\frac{n_2}{n_1+n_2}

p_1=p\times \chi_1  (Dalton's law)

0.175 atm=P\times \frac{n_1}{n_1+n_2}

0.175 atm=(2.509 n)\times \frac{n_1}{n}

n_1=0.06975 mol

Mass of 0.06975 moles of methane gas :

0.06975 mol × 18 g/mol =1.25550 g

p_2=p\times \chi_2  (Dalton's law)

0.250 atm=P\times \frac{n_2}{n_1+n_2}

0.250 atm=(2.509 n)\times \frac{n_2}{n}

n_2=0.09964 mol

Mass of 0.06975 moles of oxygen gas :

0.09964 mol × 32 g/mol =3.18848 g

Total moles of mixture = n =n_1+n_2

[/tex]=0.06975 mol+0.09964 mol=0.16939 mol[/tex]

7 0
3 years ago
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