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3 years ago

A student wants to construct a circumscribed circle of a triangle. What is the first step he should take?

Mathematics

1 answer:

Ray Of Light [21]3 years ago

4 0

Answer:

The correct answer option is B. Construct the perpendicular bisector of each side of the triangle.

Step-by-step explanation:

We are given that a student wants to construct a circumscribed circle of a triangle and we are to determine whether which of the given answer options is the first step he should take.

The student needs to first construct the perpendicular bisector of each side of the triangle.

The perpendicular bisectors of each side of the triangle are constructed such that they meet at the center of the circumbscribed circle.

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Solve for p. <---- PLEASE

Gelneren [198K]

Answer:

$p = 8$

Step-by-step explanation:

1) Divide both sides by 2.

$p + 1 = \frac{18}{2}$

2) Simplify 18/2 to 9.

$p + 1 = 9$

3) Subtract 1 from both sides.

$p = 9 - 1$

4) Simplify 9 - 1 to 8.

$p = 8$

Therefor, the answer is option A.

6 0

3 years ago

The side lengths of a triangle are 9, 12, and 15. Is this a right triangle?

andriy [413]

Answer:

<h2>Yes, this is a right triangle.</h2>

Step-by-step explanation:

Hypotenuse always have the highest number than base and perpendicular.

Hypotenuse ( h ) = 15

Base ( b ) = 9

Perpendicular ( p ) = 12

Let's see whether the given triangle is a right triangle or not

Using Pythagoras theorem:

${h}^{2} = {p}^{2} + {b}^{2}$

Plugging the values,

${15}^{2} = {12}^{2} + {9}^{2}$

Evaluate the power

$225 = 144 + 81$

Calculate the sum

$225 = 225$

Hypotenuse is equal to the sum of perpendicular and base.

So , we can say that the given lengths of the triangle makes a right triangle.

Hope this helps..

Best regards!!

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-4j-1-5j+6= pls help me

alukav5142 [94]

Answer:

-9j+5

combine like terms to get this answer

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The solutions of x2=169

tresset_1 [31]

Answer:

x=13

Step-by-step explanation:

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Solve the proportion 20/3 = ?/6.

kow [346]

Answer:

c.40

Step-by-step explanation:

the answer is 40 your welcome

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3 years ago