Consider the positively charged particles seen here. The magnitude of their combined charges is represented by the vector arrow.
If one charged particle is removed, what will be the result on the force field and how will it be illustrated? A) remain constant; no change in vector B) decreases by one; arrow length decreases by 1/3 C) decreases by one but arrow length remains constant D) decreases by a factor of 2; arrow changes direction
1 answer:
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Answer:
60
Step-by-step explanation:
We have been given the matrix;
For a 2-by-2 matrix, the determinant is calculated as;
( product of elements in the leading diagonal) - (product of elements in the other diagonal)
determinant = ( 5*4) - (8*-5)
= 20 - (-40) = 60
Answer:
The value of
Step-by-step explanation:
Given that
now to find from the given functions f(x) and f'x
let
Then put x=1 in above function we get
(from the table f(1)=3 and f(3)=6)
Therefore h(1)=6
Now to find h'(1)
Let
(since
)
put x=1 in above function we get
(From the table
and
)
Therefore