Answer:
Step-by-step explanation:
Start by factoring out a 5:
We need to find two integers that have a product of 12, and a sum of -7:
(-3)(-4)=12
-3-4=-7
We can split -7x into -3x and -4x
Factor each half separately:
![5[x(x-3)-4(x-3)]](https://tex.z-dn.net/?f=5%5Bx%28x-3%29-4%28x-3%29%5D)
Since x and -4 are both being multiplied by x-3, we can combine them:
Answer/explanation
4(3x+5)=-4
You will distribute the four to every term in the parenthesis,
12x+20=-4
Then you will combine like terms
12x+20=-4
-20 -20
12x=-24
Then you will divide 12 to isolate x
Obviously, -24 cancels out and you would get x=-2
Well right off the bat, I can see a good reason why it should boggle.
If (x+y)=6 and (x-y)=2, then (x+y)(x-y) would be 12. It can't be 20.
The first 4 lines on the paper are inconsistent, so the question in the 5th line can't be calculated.
Another possible source of uncertainty (for us, anyway) is the remarkable similarity between the way you write ' Y ' and the way you write ' 4 ' . For example, look at the ' Y⁴ ' (I think ...) in the last line.
I can't understand it can you explain it in English
Answer: 2z + 6
Step-by-step explanation: Distribute the 2 to z and 3.
