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Kaylis [27]
3 years ago
9

Solid Mg(OH)2 is mixed with water and the following reversible reaction occurs:________.

Chemistry
1 answer:
hram777 [196]3 years ago
7 0

Answer:

Mg^2+ and OH- are the chemical species present at the equilibrium. Mg(OH)2 will not affect the equilibrium.

Explanation:

Step 1: data given

Reactants are Solid Mg(OH)2 and H2O(l)

Kc1 = 1.8 * 10^-11

Step 2: The balanced equation

Mg(OH)2(s)  ⇄ Mg2+(aq) + 2OH-(aq)

Step 3: Define the equilibrium constant Kc

Kc = [OH-]²[Mg^2+]

Pure solids and liquids do not have any effect or influence on the equilibrium in the reaction. So they are not included in the equilibrium constant expression.

This means Mg^2+ and OH- are the chemical species present at the equilibrium. Mg(OH)2 will not affect the equilibrium.

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For elements (Br, Ca, Fe, Na, S, Si, and Xe) which of the following term(s) apply?
ioda

Answer:

Detail is given below.

Explanation:

Bromine: Br (Halogen and non metal)

Bromine is present in group 17 and it is called halogen.

All halogens are very reactive.

Calcium; Ca ( alkaline earth metal)

Calcium is present in group 2. It is alkaline earth metal.

It has two valance electrons.

Iron; Fe (Transition metal)

Iron is transition metal and also called d-block element.

Sodium: Na (Metal, main group element)

Sodium is metal and present in group one.

It has one valance electron.

Sulfur: S (non metal)

Sulfur is non metal. It is present in group 16.

It has six valance electrons.

Silicon: Si (metalloid)

Silicon is metalloid. It is present in group 14.

It has four valance electrons.

Xenon: Xe (Noble gas, gas at a room temperature)

it is noble gas. Xenon is present in group 18.

It is gas at a room temperature.

3 0
3 years ago
Calculate the mass of NaCO3 used in experiment. SHOW WORK — 15 points!!
Liono4ka [1.6K]

The mass of sodium bicarbonate (NaHCO₃) used in the experiment is 1.997 g

<h3>Calculating mass </h3>

From the question we are to calculate the mass of NaHCO₃ (sodium bicarbonate) used in the experiment

From the given information

Mass of empty evaporating dish = 46.233g

Mass of evaporating dish + Sodium bicarbonate = 48.230g

∴ Mass of sodium bicarbonate (NaHCO₃) = [Mass of evaporating dish + Sodium bicarbonate] - [Mass of empty evaporating dish]

Mass of sodium bicarbonate (NaHCO₃) = 48.230g - 46.233g

Mass of sodium bicarbonate (NaHCO₃) = 1.997 g

Hence, the mass of sodium bicarbonate (NaHCO₃) used in the experiment is 1.997 g

Learn more on Calculating mass here: brainly.com/question/15268826

5 0
2 years ago
How does a negative ion differ from a positive?
Ilya [14]
A negative ion or anion is an electrically charged atom or group of atoms that are formed by gaining one or more electrons. Whereas a positive ion or cation is an electrically charged atom or group of atoms that are formed by losing one or more electrons. 
The losing and gaining all occurs on the outermost shell. 
7 0
3 years ago
What are the terms that descripe these values for the element oxygen?
Serga [27]

Answer:

16 is the mass number. 8 is the atomic number.

5 0
2 years ago
I am having some trouble figuring out how to approach the following problem: A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is ti
Tanya [424]
<span>We look at the end of the day:

n(HNO3) added = 0.500*17.0/1000 = 0.00850 mol
n(NH3) = 0.200*75.0/1000 - 0.00850 = 0.00650 mol
[NH3] left = 0.00650*1000/(17.0+75.0) = 0.070652
M [OH-] = Kb * [NH3] = 0.070652*1.8*10^(-5) = 1.27174 x 10^(-6)
pOH = -log[OH-] ≈ 5.8956 pH = 14 - pOH ≈ 8.10</span>
4 0
3 years ago
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