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Kaylis [27]
2 years ago
9

Solid Mg(OH)2 is mixed with water and the following reversible reaction occurs:________.

Chemistry
1 answer:
hram777 [196]2 years ago
7 0

Answer:

Mg^2+ and OH- are the chemical species present at the equilibrium. Mg(OH)2 will not affect the equilibrium.

Explanation:

Step 1: data given

Reactants are Solid Mg(OH)2 and H2O(l)

Kc1 = 1.8 * 10^-11

Step 2: The balanced equation

Mg(OH)2(s)  ⇄ Mg2+(aq) + 2OH-(aq)

Step 3: Define the equilibrium constant Kc

Kc = [OH-]²[Mg^2+]

Pure solids and liquids do not have any effect or influence on the equilibrium in the reaction. So they are not included in the equilibrium constant expression.

This means Mg^2+ and OH- are the chemical species present at the equilibrium. Mg(OH)2 will not affect the equilibrium.

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Answer:

0.8749 grams of hydrogen gas was formed from the reaction.

Explanation:

P = Pressure of hydrogen gad= 744 Torr = 0.98 atm

(1 atm = 760 Torr)

V = Volume of hydrogen gas= 11 L

n = number of moles of hydrogen gas= ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of vapor = 27.0 °C = 300.15 K

Putting values in above equation, we get:

Using an ideal gas equation:

PV=nRT

n=\frac{PV}{RT}=\frac{0.98 atm\times 11 L}{0.0821 L atm/mol K\times 300.15 K}

n = 0.4374 moles

Mass of 0.4374 moles of hydrogen gas:

0.4374 mol × 2 g/mol = 0.8749 g

0.8749 grams of hydrogen gas was formed from the reaction.

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