1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AlexFokin [52]
2 years ago
13

3. If 90.0 grams of barium chloride react with sulfuric acid, how many

Chemistry
1 answer:
PtichkaEL [24]2 years ago
4 0

Answer:

The answer to your question is 100.8 g

Explanation:

Data

  mass of Barium chloride = 90 g

  mass of Barium sulfate = ?

Balanced chemical reaction

    BaCl₂  +  H₂SO₄   ⇒    BaSO₄  +  2HCl

Process

1.- Calculate the molar mass of BaCl₂ and BaSO₄

BaCl₂ = 137.3 + (2 x 35.5) = 208.3g

BaSO₄ = 137.3 + 32 + (16 x 4) = 233.3g

2.- Use proportions to find the mass of BaSO₄

              208.3 g of BaCl₂ --------------------- 233.3 g of BaSO₄

                90 g of BaCl₂    ---------------------   x

                              x = (90 x 233.3) / 208.3

                              x = 20997/ 208.3

                              x = 100.8 g

3.- Conclusion

There will be produced 100.8 g of BaSO₄          

You might be interested in
To prepare an acetic acid/acetate buffer, a technician mixes 30.6 mL of 0.0880 acetic acid and 21.6 mL of 0.110 sodium acetate i
enyata [817]

Answer: There are 0.00269 moles of acetic acid in buffer.

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution in ml}}     .....(1)

Molarity of acetic acid solution = 0.0880 M

Volume of solution = 30.6 mL

Putting values in equation 1, we get:

0.0880M=\frac{\text{Moles of acetic acid}\times 1000}{30.6ml}\\\\\text{Moles of acetic acid}=\frac{0.0880\times 30.6}{1000}=0.00269mol

Thus there are 0.00269 moles of acetic acid in buffer.

8 0
2 years ago
Which of the following statements is true??
iren [92.7K]
Tsunamis are caused by seismic waves
8 0
3 years ago
The ratio of boys to girls at a school
Marat540 [252]

Answer:

Si tú puedes 1-2-3-4-5-6-7-8-9-10 eso debes de ser más bien dicho sacaran Club Ojalá que te ayude Chau

Explanation:

de Ojalá que te ayude No te olvides de sacar todas las preguntas esas lo que tú dijiste y si tú promoción 123 saquen globo que quieras tú

5 0
3 years ago
Conservation of mass was discussed in the background. describe how conservation of mass (actual, not theoretical) could be check
rosijanka [135]

Conservation of mass can be checked in an experiment . There are three steps to do it in a best way:

1. Weigh all the equipment and materials required in the experiment before the experiment.

2. Avoid spillage and evaporation during the experiment.

3. Weigh all the equipment and materials after the experiment.

If the mass is conserved then weight from step 1 is equal to weight from step 3.

7 0
3 years ago
A gas cylinder contains exactly 15 moles of oxygen gas (O2). How many molecules of oxygen are in the cylinder?
erik [133]
The answer is C.) 9.03 * 10^24
5 0
3 years ago
Other questions:
  • A sealed container filled with argon gas at 35°C has a pressure of 832 torr. If the volume of the container is decreased by a fa
    11·1 answer
  • What is a fuel produced by fermenting crops.
    15·1 answer
  • What is the mass of 3.8 × 1024 atoms of argon (Ar)?
    11·1 answer
  • What are the coefficients needed to balance the equation for the combustion of
    12·2 answers
  • The mother of a child has a cleft chin while the father of a child has a smooth chin. The child also has a cleft chin
    7·1 answer
  • There are many diverse species of plants and animals
    14·1 answer
  • Choose the most alkaline substance in the group.
    8·1 answer
  • 50.00 ml of nitric acid (of unknown
    13·1 answer
  • HELP THIS IS SCIENCE I HAVING TROUBLE
    13·2 answers
  • How many moles is 8.35x 10^25
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!