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Firdavs [7]
3 years ago
10

A child has a small rubber ball that is filled with water and glitter. When the ball is bounced the glitter spreads around the i

nside of the toy then settles back at the bottom. The mixture inside the toy would be considered which of the following?
Homogeneous


Solution


Heterogeneous


Colloid
Chemistry
1 answer:
elena55 [62]3 years ago
7 0

Answer:

Heterogeneous

Explanation:

<u>A heterogeneous mixture is a non-uniform composition in which particles of far larger size are suspended in a phase and can be easily separated from each other. In a heterogeneous mixture, the gravity pulls the suspended particles down out of solution.</u>

The given example is a heterogeneous mixture in which glitter particles are suspended inside the toy and settles back at the bottom due to gravity. The glitter particles can also easily separated from the toy.

Hence, the correct answer is "Heterogeneous".

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It provides a way to test a hypothesis

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Classify each of the following substances:
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Explanation:

Carbon dioxide is a polar molecule whose positive center is on the carbon atom: This positive center is able to attract (and accept) the lone electron pairs present on the oxide ion (O2-). carbon dioxide is acts as a Lewis acid

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Copper (II) sulfate pentahydrate may be heated to drive off the water of hydration. If 5 g of water are produced, what was the o
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Answer:

13.9g of CuSO4•5H2O

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CuSO4•5H2O → CuSO4 + 5H2O

Next, we shall determine the mass of CuSO4•5H2O heated and the mass of H2O produced from the balanced equation.

This is illustrated below

Molar mass of CuSO4• 5H2O = 63.5 + 32 + (16x4) + 5(2x1 + 16)

= 63.5 + 32 + 64 + 5(18) = 249.5g/mol

Mass of CuSO4•5H2O from the balanced equation = 1 x 249.5 = 249.5g

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H2O from the balanced equation = 5 x 18 = 90g

From the balanced equation above,

249.5g of CuSO4•5H2O produced 90g of H2O.

Now, we can determine the mass of CuSO4•5H2O needed to produce 5g of H2O. This can be achieved as shown below:

From the balanced equation above,

249.5g of CuSO4•5H2O produced 90g of H2O.

Therefore, Xg of CuSO4•5H2O will produce 5g of H2O i.e

Xg of CuSO4•5H2O = (249.5 x 5)/90

Xg of CuSO4•5H2O = 13.9g

Therefore, 13.9g of CuSO4•5H2O is needed to produce 5g of H2O.

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