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erik [133]
3 years ago
12

Fan object moves in uniform circular motion in a circle of radius R=200 meters, and the objectes 5.00 seconds to

Physics
1 answer:
Leviafan [203]3 years ago
6 0

Answer:

The centripetal acceleration of the object is 31550.72\ m/s^2.  

Explanation:

We have,

Radius of a circular path is 200 m

It takes 5 seconds to complete 10 revolutions. The angular velocity of the object is given by the rate of change of angular displacement per unit time :

\omega=\dfrac{\Delta \theta}{\Delta t}\\\\\omega=\dfrac{2\pi \times 10}{5}\\\\\omega=12.56\ rad/s

The centripetal acceleration of the object is given by :

a=\omega^2 r\\\\a=(12.56)^2 \times 200\\\\a=31550.72\ m/s^2

So, the centripetal acceleration of the object is 31550.72\ m/s^2.

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3 years ago
Reading Check: (Describe) how pressure changes as the velocity of a fluid<br> increases.
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Answer:

Bernoulli's equation states mathematically that if a fluid is flowing through a tube and the tube diameter decreases, then the velocity of the fluid increases, the pressure decreases, and the mass flow (and therefore volumetric flow) remains constant so long as the air density is constan

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Which term best describes a fad diet
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3 years ago
A sled is at rest at the top of a slope 2 m high. The sled has a mass of 45 kg. What is the sled's potential energy?
kap26 [50]

Answer:

PE = 882 J

Explanation:

Through the International System we know that the gravity of the earth is 9.8 m/s², so...

Data:

  • m = 45 kg
  • g = 9.8 m/s²
  • h = 2 m
  • PE = ?

Formula:

  • \boxed{\bold{PE=m*g*h}}

Replace and solve:

  • \boxed{\bold{PE=45\ kg*\ 9.8\frac{m}{s^{2}}*2\ m}}
  • \boxed{\boxed{\bold{PE=882\ J}}}

The potential energy of the sled is <u>882 Joules</u>.

Greetings.

8 0
3 years ago
Please help ASAP. A car engine with a mass of 1750 kg can exert 215 000 W. a) How long will it take the car to reach 95.0 km/h i
tensa zangetsu [6.8K]
<h2>Answer:</h2><h3><u>QUESTION①)</u></h3>

<em>✔ First step : calculate the kinetic energy that this car requires to reach 95 km/h</em>

95/ 3,6 ≈ 26,4 m/s  

<em>Ec = ½ m x V²  </em>

With Ec in J; m in kg; and V in m/s  

  • Ec = ½ 1750 x 26,4²  
  • Ec ≈ 610 000 J

<em>✔ Knowing that the car has a p power of 215,000 W, so : </em>

T = E/P  

  • T = 610 000/215 000  
  • T ≈ 2.8 s
<h3>The car takes 2.8 s to reach 95 km/h </h3>

<h3><u>QUESTION②)</u></h3>

N = 2,8/6,5 x 100 = 43.07

<h3>The car efficiency is 43 % </h3>
5 0
3 years ago
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