Answer:
Work done, W = 6153.31 Joules
Explanation:
It is given that,
Weight of piano, W = F = 7382 N
It is pushed 2.16 meters friction less plank
The angle with horizontal,
When the piano slide up plank at a slow constant rate. The y component of force is taken into consideration. The net force acting on it is given by :
Work done is given by :
W = 6153.31 Joules
So, the work done in sliding the piano up the plank is 6153.31 Joules. Hence, this is the required solution.
Answer:
<em>0.44 m/s^2</em>
Explanation:
initial velocity = 0 (since the child starts from rest)
distance covered by the child = 2 m (the length of the slide)
time taken = 3 sec
acceleration of the child = ?
using Newton's equation of motion
s =
where s is the distance covered by the child
u is the initial velocity
a is the acceleration
t is the time spent
substituting values, we have
2 = 0(3) +
2 = 9a/2
4 = 9a
a = 4/9 = <em>0.44 m/s^2</em>
Answer:
0 degrees
Explanation:
Let are two forces. The resultant of two forces acting on the same point is given by :
Where is the angle between two forces
When i.e. when two forces are parallel to each other,
When i.e. when two forces are parallel to each other,
When i.e. when two forces are parallel to each other,
It is clear that the resultant of two forces acting on the same point simultaneously will be the greatest when the angle between them is 0 degrees. Hence, this is the required solution.
The centripetal acceleration of an object is given by the relation,
where Ac = centripetal acceleration =
R = radius of rotation = 15 m
V = speed of astronaut
Hence,
solving this we get, V = 38.34 m/s