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Vitek1552 [10]
3 years ago
13

A 7382 N piano is to be pushed up a(n) 2.16 m frictionless plank that makes an angle of 22.7 ◦ with the horizontal. Calculate th

e work done in sliding the piano up the plank at a slow constant rate. Answer in units of J.
Physics
1 answer:
lubasha [3.4K]3 years ago
7 0

Answer:

Work done, W = 6153.31 Joules

Explanation:

It is given that,

Weight of piano, W = F = 7382 N

It is pushed 2.16 meters friction less plank

The angle with horizontal, \theta=22.7^{\circ}

When the piano slide up plank at a slow constant rate. The y component of force is taken into consideration. The net force acting on it is given by :

F_y=F\ sin\theta

Work done is given by :

W=F_y\times d

W=F\ sin\theta \times d

W=7382 sin(22.7) \times 2.16

W = 6153.31 Joules

So, the work done in sliding the piano up the plank is 6153.31 Joules. Hence, this is the required solution.

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