Question

A 7382 N piano is to be pushed up a(n) 2.16 m frictionless plank that makes an angle of 22.7 ◦ with the horizontal. Calculate the work done in sliding the piano up the plank at a slow constant rate. Answer in units of J.

Answer 1

Answer:

Work done, W = 6153.31 Joules

Explanation:

It is given that,

Weight of piano, W = F = 7382 N

It is pushed 2.16 meters friction less plank

The angle with horizontal, $\theta=22.7^{\circ}$

When the piano slide up plank at a slow constant rate. The y component of force is taken into consideration. The net force acting on it is given by :

$F_y=F\ sin\theta$

Work done is given by :

$W=F_y\times d$

$W=F\ sin\theta \times d$

$W=7382 sin(22.7) \times 2.16$

W = 6153.31 Joules

So, the work done in sliding the piano up the plank is 6153.31 Joules. Hence, this is the required solution.